i need to reshape rows that are in complicated manner!

I have data in rows which is a bit complicated to arrange i need a code that will arrange in columns.

 Example: 
If A=
   [1 3 5 7 9
   2 4 6 8 10
   1 3 5 7 9 
   2 4 6 8 10      
   1 3 5 7 9 
   2 4 6 8 10
   1 3 5 7 9 
   2 4 6 8 10]

thats what data looks like. 1 and 2 rows contains data of same category so i want them to be arranged in a single column,same goes for the other three pairs in total i need 4 columns. but the reshaping command will put the 2nd column 1st value exactly after last value.

Answer 1

[Roger Stafford]

The number of rows in A must be even.

n = size(A,2);
B = reshape(A.’,2*n,[]); 
B = B(ceil((1:2*n)/2)+n*mod(0:2*n-1,2),:);

[Mahrukh Farooq]

Fantastic it worked Thankyou sooo much:) im beginner so can you please explain me this part of the code? how it works?

B = B(ceil((1:2*n)/2)+n*mod(0:2*n-1,2),:);

[Roger Stafford]

In the quantity

p = ceil((1:2*n)/2)+n*mod(0:2*n-1,2)

what we need is

p = [1,1+n,2,2+n,3,3+n,...]

in order to do the proper rearrangement. The first term will be:

ceil((1:2*n)/2) = [1,1,2,2,3,3,...]

and the second term will give:

n*mod(0:2*n-1,2) = [0,n,0,n,...]

Adding these together gives the p that we require.

[Mahrukh Farooq]

Thanks a lot again!

Answer 2

[John D'Errico]

Easy.

A = reshape(A',10,4);
A =
   1     1     1     1
   3     3     3     3
   5     5     5     5
   7     7     7     7
   9     9     9     9
   2     2     2     2
   4     4     4     4
   6     6     6     6
   8     8     8     8
  10    10    10    10

Answer 3

[Mahrukh Farooq]

Output should look this

A=[1  1  1  1
   2  2  2  2
   3  3  3  3
   4  4  4  4
   5  5  5  5
   6  6  6  6
   7  7  7  7
   8  8  8  8
   9  9  9  9
  10  10 10 10]

C1 is a combination of R1 and R2 same goes for others.