take part of cell depend on vector

Dear all, I have cell (a) and vector (b), I wanna check each number in b that repeat it in a and take each cell from (a) make it as vector by loop.

 a=[{[1,9,79,3]  [2,29,16,7,3] 3 [4,74,3] [5,73,79,3] [6,56,3] [7,3]}] ;
 b=[ 79 3 74 10];

results should be as follow:

 cell-part 79= [1,9,79,3,5,73,79,3]
 cell_part 3 = [1,9,79,3,2,29,16,7,3,3,4,74,3,5,73,79,3,6,56,3,7,3];
 cell_part 74 = [4,74,3]
 cell_part 10 = {0};

[Stephen23]

Continuation of this question:

https://www.mathworks.com/matlabcentral/answers/318605-compare-between-vector-and-cell

Answer 1

[Stephen23]

As you were already told in your last question, this is not a good idea: naming variables dynamically will make your code slow, buggy, and hard to follow. Read this to know why:

https://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval

A much better solution is to learn to use indexing, which is fast and efficient:

 >> a = {[1,9,79,3],[2,29,16,7,3],3,[4,74,3],[5,73,79,3],[6,56,3],[7,3]};
 >> b = [79,3,74,10];
 >> idc = cellfun(@(x)any(bsxfun(@eq,x,b(:)),2),a,'Uni',0);
 >> out = cellfun(@(x)[a{x}],num2cell([idc{:}],2),'Uni',0);

which gives exactly the output vectors that you specified, inside the cell array out:

>> out{1}
ans =
     1     9    79     3     5    73    79     3
>> out{2}
ans =
  Columns 1 through 15
     1     9    79     3     2    29    16     7     3     3     4    74     3     5    73
  Columns 16 through 22
    79     3     6    56     3     7     3
>> out{3}
ans =
     4    74     3
>> out{4}
ans =
     []

[skysky2000]

Thanks alot Stephen,