Either I or matlab is going crazy with vertcat using brackets

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Someone please point out what is going on with this piece of code. Matlab is running the first 3 concatenations fine, and not the last one. It's driving me crazy. It spits out
Error using vertcat Dimensions of matrices being concatenated are not consistent.
for that line. Please help. Thanks!
e = [1 1 1 1];
vertcat( 2*(e(2)*e(4) - e(3)*e(1)),2*(e(3)*e(4) + e(2)*e(1)),e(4)^2 + e(1)^2 - e(2)^2 -e(3)^2); % calling vertcat works
[ 2*(e(2)*e(4) - e(3)*e(1)) 2*(e(3)*e(4) + e(2)*e(1)) e(4)^2 + e(1)^2 - e(2)^2 -e(3)^2]; % horizontal works
% subing in works
a = 2*(e(2)*e(4) - e(3)*e(1)); b = 2*(e(3)*e(4) + e(2)*e(1)); c = e(4)^2 + e(1)^2 - e(2)^2 -e(3)^2;
[a; b; c]
% but this doesn't work for some reason...
[ 2*(e(2)*e(4) - e(3)*e(1));2*(e(3)*e(4) + e(2)*e(1));e(4)^2 + e(1)^2 - e(2)^2 -e(3)^2];

Accepted Answer

Stephen23
Stephen23 on 13 Jan 2017
Edited: Stephen23 on 13 Jan 2017
MATLAB is doing exactly as documented:
"Blank spaces around operators such as -, :, and ( ), are optional, but they can improve readability... However, blank spaces act as delimiters in horizontal concatenation"
Because of this you have unknowingly used horzcat (via []) to generate different length vectors, which then cannot be concatenated together using vertcat. This is trivial to demonstrate, because basically you are doing this:
>> [1+2 2 -3]
ans =
3 2 -3
But I think now you can see why this is not a vector with two values, as you expect it to be. Instead, MATLAB is doing exactly as its documentation states it should. Learn to read the documentation instead of going crazy.
Your first two examples, with vertcat and horzcat are not doing what you think they are. In the case of vertcat because the input arguments are not being concatenated in themselves: they are simply interpreted as operations to be evaluated before being passed to vertcat. It is much as if you did this:
x1 = 2*(e(2)*e(4) - e(3)*e(1));
x2 = 2*(e(3)*e(4) + e(2)*e(1));
x3 = e(4)^2 + e(1)^2 - e(2)^2 -e(3)^2;
vertcat(x1,x2,x3)
because MATLAB already knows that they are input arguments to a function and are not in themselves being concatenated (this only happens inside vertcat). Perhaps what you did not check is the output of these two examples: did you notice that they have different number of terms? The reason should be clear by now.
Summary: learn to read the documentation (this is the best thing any MATLAB learner can do). And never rely on space characters to create vectors or matrices. Although loved by some, using space characters leads to exactly the problems that you see here. Much clearer is to always specify vectors and matrices using commas and semi-colons. Then the code intent is always perfectly clear:
>> [1+2 2 -3] % is this a mistake? Should it be 2-3 ?
ans =
3 2 -3
>> [1+2, 2-3] % comma makes separation clear
ans =
3 -1
  2 Comments
Sam Swanson
Sam Swanson on 14 Jan 2017
Ya... that was dumb. It'd been a long day. Thank you very much

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More Answers (1)

John BG
John BG on 13 Jan 2017
Edited: John BG on 13 Jan 2017
Sam
Remove all spaces in the crashing line.
[2*(e(2)*e(4)-e(3)*e(1));2*(e(3)*e(4)+e(2)*e(1));e(4)^2+e(1)^2-e(2)^2-e(3)^2]
=
0
4
0
MATLAB was attempting to take in matrix with rows of different lengths because of the way you placed the expressions, spaces, '+' and '-'.
.
Sam
if you find these lines useful would you please mark my answer as Accepted Answer?
To any other reader, if you find this answer of any help please click on the thumbs-up vote link,
thanks in advance for time and attention
John BG
  3 Comments
Jan
Jan on 15 Jan 2017
Edited: Jan on 15 Jan 2017
Removing all spaces from the code is a bad idea, because it impedes the readability and therefore the debugging. A general rule is to add spaces about binary operators and no space after the unary minus:
x = a + -b;
Nevertheless, I agree that the interpretation of "- 3" and "-3" is ambiguos in Matlab. Allowing the space as a separator between columns and the linebreak for rows was a bad idea from MathWorks. Without this try to be smart, there would not be a problem with spaces around the operators in arrays.

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