# for loop

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Kugen Raj on 22 Mar 2012
if size(qq)==[1,8]
ff=[(hh(1,1)+qq(1,2))];
ff1=[(hh(1,1)+qq(1,4))];
ff2=[(hh(1,1)+qq(1,6))];
ff3=[(hh(1,1)+qq(1,8))];
aa=kk(ff);
aa1=kk(ff1);
aa2=kk(ff2);
aa3=kk(ff3);
elseif size(qq)==[1,6] / size(qq)==[1,7]
ff=[(hh(1,1)+qq(1,2))];
ff1=[(hh(1,1)+qq(1,4))];
ff2=[(hh(1,1)+qq(1,6))];
aa=kk(ff);
aa1=kk(ff1);
aa2=kk(ff2);
elseif size(qq)==[1,4] / size(qq)==[1,5]
ff=[(hh(1,1)+qq(1,2))];
ff1=[(hh(1,1)+qq(1,4))];
aa=kk(ff);
aa1=kk(ff1);
elseif size(qq)==[1,2] / size(qq)==[1,3]
ff=[(hh(1,1)+qq(1,2))];
aa=kk(ff);
end
based on my coding, i want to calculate (aa-aa3) if the size(qq)=[1,8], (aa-aa2) if size(qq)=[1,6], (aa-aa1) of size(qq)=[1,4] and (aa only) if the size(qq)=[1,2]. Is this code correct because im not sure if it works properly.

Nathan Greco on 22 Mar 2012
The only thing that doesn't look right to me is where you have
elseif size(qq)==[1,#] / size(qq)==[1,#+1]
Where # is 6,4,2 Why do you have the second half there? I would get rid of that and just put
elseif size(qq)==[1,#]
And so on. Note: If you wanted to say if size(qq) is less than or equal to [1,3], you would need an | as such:
elseif size(qq)==[1,#] | size(qq)==[1,#+1]
-Nathan
##### 2 CommentsShowHide 1 older comment
Nathan Greco on 22 Mar 2012
Yes, just replace your /'s with |'s.

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