Possible to find if a portion of an array equals an array of the same size as the portion?

I have a school project where I have written a program that creates a simple binary array based on inputs. The output array usually looks something like this:

X = [1 0 0 0 0 1 0 1 0]

I need to write a simple script that will convert this to material type, for which I have the key. Basically, if the last 3 elements of the array ([0 1 0]) equal to [0 1 0], then my material is Red Glass. They could potentially equal 3 other possibilities. If the array elements 2 through 6 ([0 0 0 0 1]) equal [0 0 0 0 1], then my material is type 1 zero and type 2 zero. There are potentially 15 other possibilities of what these specific elements might be. The first element of the array is always 1, and does not matter.

I basically need to write a script that is an IF function that asks if the last 3 elements of the array equal this, this, or that, then I have THIS (and so on), and then do the same thing for elements 2-6, and then pair up the conclusions.

Answer 1

[Prannay Jain]

Yes, it is possible to compare a part of an array with another array of the same size of sub-array.

You will have to write lots of if condition to match the sub-array. For example,

X = [1 0 0 0 0 1 0 1 0];
n = X(7:9);
if(n == [0 1 0])
  disp('Red Glass'); 
  output = 'Red Glass';  %%or store it in some other variable
elseif (n == [1 1 1])
  disp('Blue Glass')
else
  disp('Something else')
end
output

Similarly, you can do for index 2 to 6,

m = X(2:6)

and write if conditions.