# polar plot

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Pinco on 6 Apr 2012
Answered: Sanchari on 25 Jul 2024 at 1:16
Hi everyone! I want to plot a function like that:
the plot is in fig. 138 (c) and its expression in Ms.
What's the code?
because, I think, there is a scale factor, I use this code:
ts=linspace(0,2*pi,500);
Ms = 1-ts.*sin(ts)-0.5*cos(ts);
polar(ts,Ms)
but this generates a wrong plot. How can I do this?

Sanchari on 25 Jul 2024 at 1:16
Hello Pinco,
The link provided does not work. However, to create a polar plot of the equation provided: [ M_s = 1 - t \sin(t) - 0.5 \cos(t) ], the following code can be used:
% Define the range for the variable t
ts = linspace(0, 2*pi, 500);
% Compute the values of Ms using the given equation
Ms = 1 - ts .* sin(ts) - 0.5 * cos(ts);
% Create the polar plot
figure;
polarplot(ts, Ms);
title('Polar Plot of M_s = 1 - t \cdot sin(t) - 0.5 \cdot cos(t)');
Output:
There can be additional customizations like adding grid lines, setting axis limits, or changing the line style and colour. Here's an example with these additional customizations:
% Define the range for the variable t
ts = linspace(0, 2*pi, 500);
% Compute the values of Ms using the given equation
Ms = 1 - ts .* sin(ts) - 0.5 * cos(ts);
% Create the polar plot
figure;
polarplot(ts, Ms, 'r', 'LineWidth', 1.5); % Red color and thicker line
title('Polar Plot of M_s = 1 - t \cdot sin(t) - 0.5 \cdot cos(t)');
% Customize the polar plot
ax = gca;
ax.ThetaGrid = 'on'; % Turn on theta grid
ax.RGrid = 'on'; % Turn on radial grid
ax.ThetaTick = 0:45:360; % Set theta tick marks every 45 degrees
Output:
Notes:
1. Ensure that the function to be plot matches with the one intended.
2. Adjust the radial limits "ax.RLim" as needed to ensure that the plot is displayed correctly.
3. Further customizations are possible using properties of "polarplot" and "axes" objects.
Hope this helps!