How do I use intersect(A,B,'legacy') correctly in my case?

Hello MATLAB community, I am currently using a code from a scientific paper. The code was written with MATLAB 2012b, which means that the behaviour of 'intersect' has changed in newer releases. In order to run the code properly I have to replace all intersect(A,B) by intersect(A,B,'legacy'),according to https://de.mathworks.com/help/matlab/ref/intersect.html . Unfortunately I ran into a problem in this part of the code:

for i=1:N
    gvarspecstartemp = [];
    for j=1:cstypenum
        eval(['starvec.vars{i,j} = intersect(gvarspec.',char(cskeys(i,1)),'.star,endovecfull{j});'])
        gvarspecstartemp = [gvarspecstartemp, starvec.vars{i,j}];
    end
    eval(['gvarspec.',char(cskeys(i,1)),'.star = gvarspecstartemp;'])   
end

I do not know how to replace the command in

eval(['starvec.vars{i,j} = intersect(gvarspec.',char(cskeys(i,1)),'.star,endovecfull{j});'])

I already tried these ways:

eval(['starvec.vars{i,j} = intersect(gvarspec.',char(cskeys(i,1)),'.star,endovecfull{j},'legacy');'])
eval(['starvec.vars{i,j} = intersect(gvarspec.',char(cskeys(i,1)),'.star,endovecfull{j},legacy);'])

The code can be found here http://www.sciencedirect.com/science/article/pii/S0014292115000197 in Appendix B.

I would really appreciate your help. Thank you.

[Stephen23]

https://www.mathworks.com/help/matlab/matlab_prog/string-evaluation.html

https://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval

[John D'Errico]

We can't apply +1 on a comment. :(

Answer 1

[the cyclist]

I think you want

eval(['starvec.vars{i,j} = intersect(gvarspec.',char(cskeys(i,1)),'.star,endovecfull{j},''legacy'');'])

You need to double the single-quote characters, to tell MATLAB that they are part of the string, not delimiting the string.

[the cyclist]

... but I 100% agree with Stephen's comment on your question.

[Marjo Kaul]

Thank you very much for your fast response!