filenames = {'DY463269-F 01-01-2017.xlsx'
'DY463269-F 01-01-2017.xlsx'
'DY463271-8 01-01-2017.xlsx'
'DY466290-M 01-01-2017.xlsx'};
fileinfo_cell = regexpi( filenames, '^(?<serial>[a-z]{2}\d{6}[a-z\-]{0,2})\s+(?<date>\d\d-\d\d-\d\d)', 'names','lineanchors');
fileinfo = vertcat(fileinfo_cell{:});
fileinfo will then be a struct array with fields "serial" and "date".
With that particular set of data, the struct will have 3 elements, because DY463271-8 01-01-2017.xlsx does not match the pattern (the serial ends in -8 but the pattern does not permit numbers at that point.)
A generalization of the pattern would be
fileinfo = regexpi( filenames, '^(?<serial>\w\w\d{6}[\w-]{0,2})\s+(?<date>\d\d-\d\d-\d\d)', 'names','lineanchors')
Each \w corresponds to [a-z0-9_] -- the "word-building" characters. What you have now is more focused and you might need that focus, but sometimes it is useful to be more lenient.
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