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Regexp to filter file names

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maxroucool
maxroucool on 19 Oct 2017
Commented: maxroucool on 20 Oct 2017
Hello,
I would like to use a regexp to filter file names contained in a folder. I almost got it, but I have trouble handling cell that output the dir() function...
Let's imagine I have these files in the data folder :
DY463269-F 01-01-2017.xlsx
DY463269-F 01-01-2017.xlsx
DY463271-8 01-01-2017.xlsx
DY466290-M 01-01-2017.xlsx
My code is :
filesList = dir('data/');
serialList = regexpi({filesList.name}, '[a-z]{2}[0-9]{6}[a-z\-]{0,2}', 'match')
dateList = regexpi({filesList.name}, '[0-9]{2}-[0-9]{2}-[0-9]{2}', 'match')
data = cell2struct([serialList; dateList],{'Name','Date'},1)
data(3).Name
First, I guess we can do only one regexpi to get both information... But mostly, data(3).Name return me a cell and I would like it to simply be a string.
Any idea to fix this?
Thanks,
Max

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Accepted Answer

Walter Roberson
Walter Roberson on 19 Oct 2017
filenames = {'DY463269-F 01-01-2017.xlsx'
'DY463269-F 01-01-2017.xlsx'
'DY463271-8 01-01-2017.xlsx'
'DY466290-M 01-01-2017.xlsx'};
fileinfo_cell = regexpi( filenames, '^(?<serial>[a-z]{2}\d{6}[a-z\-]{0,2})\s+(?<date>\d\d-\d\d-\d\d)', 'names','lineanchors');
fileinfo = vertcat(fileinfo_cell{:});
fileinfo will then be a struct array with fields "serial" and "date".
With that particular set of data, the struct will have 3 elements, because DY463271-8 01-01-2017.xlsx does not match the pattern (the serial ends in -8 but the pattern does not permit numbers at that point.)
A generalization of the pattern would be
fileinfo = regexpi( filenames, '^(?<serial>\w\w\d{6}[\w-]{0,2})\s+(?<date>\d\d-\d\d-\d\d)', 'names','lineanchors')
Each \w corresponds to [a-z0-9_] -- the "word-building" characters. What you have now is more focused and you might need that focus, but sometimes it is useful to be more lenient.

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maxroucool
maxroucool on 20 Oct 2017
Perfect thank you Walter!

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More Answers (1)

Guillaume
Guillaume on 19 Oct 2017
Note that the reason you get cell arrays in your structure is because as you've used it regexpi returns a cell array of cell arrays of char arrays as there can be more than one match per filename. Adding the 'once' option to these regexpi calls would tell them that there can only ever be more than one match and as a result you'd get a cell array of char arrays, which would give you the structure you expect.
serialList = regexpi({filesList.name}, '[a-z]{2}[0-9]{6}[a-z\-]{0,2}', 'match', 'once');
dateList = regexpi({filesList.name}, '[0-9]{2}-[0-9]{2}-[0-9]{2}', 'match', 'once');

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maxroucool
maxroucool on 20 Oct 2017
Perfect thank you Guillaume!

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