how can i solve problem in my code for adaptive median filter

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function f= dd(r,Smax)
if (Smax <= 1) | (Smax/2 == round(Smax/2)) | (Smax ~= round(Smax))
error('SMAX must be an odd integer > 1.')
end
[M, N] = size(r);
% Initial setup.
f = r;
f(:) = 0;
alreadyProcessed = false(size(r));
%Begin filtering.
for k = 3:2:Smax
zmin = ordfilt2(r, 1, ones(k, k), 'symmetric');
zmax = ordfilt2(r, k * k, ones(k, k), 'symmetric');
zmed = medfilt2(r, [k k], 'symmetric');
processUsingLevelB = (zmed > zmin) & (zmax > zmed) & ...
~alreadyProcessed;
zB = (r > zmin) & (zmax > r);
outputZxy = processUsingLevelB & zB;
outputZmed = processUsingLevelB & ~zB;
f(outputZxy) = r(outputZxy);
f(outputZmed) = zmed(outputZmed);
alreadyProcessed = alreadyProcessed | processUsingLevelB;
if all(alreadyProcessed(:))
break;
end
end
% Output zmed for any remaining unprocessed pixels. Note that this
% zmed was computed using a window of size Smax-by-Smax, which is
% the final value of k in the loop.
f(~alreadyProcessed) = zmed(~alreadyProcessed);
  1 Comment
Daleel Ahmed
Daleel Ahmed on 28 Oct 2017
Edited: Walter Roberson on 28 Oct 2017
Error using ordfilt2
Expected input number 1, A, to be one of these types:
double, single, uint8, uint16, uint32, uint64, int8, int16, int32, int64, logical
Instead its type was char.

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Accepted Answer

Walter Roberson
Walter Roberson on 28 Oct 2017
You appear to be attempting to pass in characters for the first input to your function, the one named "r" here. That input must be numeric for this code to work.

More Answers (1)

Zeeshan Salam
Zeeshan Salam on 24 Mar 2019
can u send me working of this algorithm and flowchart

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