Naming Variables wit using varargin.

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Hello everyone. I define a Gama function which must had 4 inputs. If we entered more than 4 inputs it should say Error!. I must use the variables that taken from inside of the varargin to an equation like this fun= (sin(2*pi.*f.*(m-n).*T))/ 2*pi.*f.*(m-n).*T; but how can i name my variables? For example if i entered Gama(1,3,5,7) the first value should represents m ,the second value should represents n and the others represents f and t. How can i name them and use it into my function. Thanks for your help. Have a Good Day.
function Gama(varargin)
if nargin<=4
disp("Number of input arguments: " + nargin)
disp(varargin)
else
'Error'
f=varargin{1}
m=varargin{2}
n=varargin{3}
T=varargin{4}
if nargin<=4
fun= (sin(2*pi.*f.*(m-n).*T))/ 2*pi.*f.*(m-n).*T;
t=1:1:100;
figure
plot(fun,t)
xlabel('Omega')
ylabel('Gamma')
else
'Error! More Than 4 Inputs entered'
end
  1 Comment
Stephen23
Stephen23 on 9 Jan 2021
Why do academics insist on teaching such bizarre, unrealistic, and ugly practices? This should simply be:
function Gama(f,m,n,T)
Using named arguments directly is simpler, more efficient (no allocating data to new variables), still throws an error for too many input arguments, and MATLAB shows the variable names when calling the function:
Whereas using varargin shows nothing useful at all:

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Accepted Answer

Walter Roberson
Walter Roberson on 31 Oct 2017
Minor modifications are needed
function Gama(varargin)
if nargin < 4
error('Not enough inputs entered')
elseif nargin > 4
error('Too many inputs entered')
end
f=varargin{1}
m=varargin{2}
n=varargin{3}
T=varargin{4}
T=1:1:100;
fun= (sin(2*pi.*f.*(m-n).*T))/ 2*pi.*f.*(m-n).*T;
figure
plot(T, fun)
xlabel('Omega')
ylabel('Gamma')
I would, however, recommend that you consider the possibility that you instead want
fun= (sin(2*pi.*f.*(m-n).*T)) ./ (2*pi.*f.*(m-n).*T);
  1 Comment
Bgr Mrt
Bgr Mrt on 1 Nov 2017
Thank you for your response. Have a good day.

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