Intersection of plane and line.

what is the code to find the intersection of the plane x + 2y + 3z = 4 and line (x, y, z) = (2,4,6) + t(1,1,1)?

Answer 1

[Star Strider]

One approach:

syms x y z t
%    x + 2y + 3z = 4 and line (x, y, z) = (2,4,6) + t(1,1,1)
xl = 2 + t;
yl = 4 + t;
zl = 6 + t;
Eqn = x + 2*y + 3*z == 4;
Eqn = subs(Eqn, {x y z},{xl yl zl});
t = solve(Eqn, t)

Then, substitute back into the ‘line’ equations for ‘xl’, ‘yl’, and ‘zl’.

[Stephanie Ciobanu]

it won't print anything

[Star Strider]

It gave me:

t =
-4

in R2017b. This would yield:

xl = -2
yl =  0
zl = +2

Be sure you don’t have a semicolon at the end of the solve call line. That will suppress the output to the Command Window.