Assign an array of structs to a cell

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Hi, I have a variable sized array of structs that I read and want to assign to cell within a cell array. I found a results for "Conversion to cell from struct is not possible." in prior questions but that maps a single struct to a single cell. I would like to be able to store an array of structs to a cell. Is that possible? How? Thanks, Jerry
  7 Comments
Jerry Olup
Jerry Olup on 17 Nov 2017
Stephen, >> Beginners often import data as string because they do not use the importing tools very effectively.
Ah, regarding importing of data:
The data is mixed between numbers (all modes, literally) and strings. It is also variable length with fields missing or having a few modes (including numeric or string, causing decisions in interpretation). That's why I ran it all as strings (with a lot, hence the ..., of code omitted). from that I can parse variations of the file effectively.
This imports all data in a few mins, so I am satisfied with the performance.
It's not regular or academic data...!
The code excerpts are meant to point out that this is storing an array of structs into a single cell.
Thanks, Jerry
Stephen23
Stephen23 on 17 Nov 2017
Edited: Stephen23 on 17 Nov 2017
"However I am trying to assign an array of structures to a single cell."
I still do not see what the problem is. Any variable can be allocated to a cell, the fact your structure is non-scalar is irrelevant. Here is a non-scalar structure array being allocated to a cell:
>> S(1).data = 1;
>> S(2).data = 3;
>> C{1} = S;
That test code throws no errors, no problems doing exactly what you state: "assign an array of structures to a single cell."
"Instead I hav to access each structure through dot indexing"
You put the data into an structure yourself! How else would you expect to access it?

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Accepted Answer

Stephen23
Stephen23 on 17 Nov 2017
Edited: Stephen23 on 17 Nov 2017
In your example code you need to change the indexing into the cell array from i to k:
carray{k} = results;
  2 Comments
Jerry Olup
Jerry Olup on 17 Nov 2017
And... tested, so it's fine to store any data in cell as expected. Simple indexing error. Thx again.

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