Setting variable to zero with conditional statement?

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I'm writing a for loop which runs through values and sometimes the element that the loop selects is outwith the vector length.
For example, say I have a vector of 10 entries and the loop asks for the 11 "th" entry it doesn't exist so I get an error.
How do I put this in the code with an if statement? I want the code to go like:
%the loop selects y(n)
if n>10 then set y(n) = 0
else y(n) = y(n)
Sorry if it's unclear, I'm sure it's a simple fix?
  2 Comments
Jose Marques
Jose Marques on 19 Nov 2017
Could you post your entire code? So we can help you better
matlabkid602
matlabkid602 on 19 Nov 2017
Edited: Walter Roberson on 19 Nov 2017
shift = k-n;
if shift <1 || shift >21
y(shift) = 0;
end

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Answers (1)

Walter Roberson
Walter Roberson on 19 Nov 2017
if n>length(y); y(n) = 0; end
  3 Comments
Walter Roberson
Walter Roberson on 19 Nov 2017
If I understand correctly, for negative shift you would like to set array locations with negative indices? That is not permitted in MATLAB. Do you want negative shift to be interpreted as starting from the maximum value, with n = -1 being interpreted the same as y(end) and n = -2 being interpreted the same as y(end-1) ?
matlabkid602
matlabkid602 on 19 Nov 2017
Edited: matlabkid602 on 19 Nov 2017
If I choose k such that somewhere during the loop "shift" becomes negative, or greater than the length of y, I want y(shift) = 0.
I'm solving ODE's with the loop and need this condition.

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