Indexing for cell arrays

I have 10x1300 cell array z, how do i find a certain value of z using indexing

find(abs(z-z_position)<intvl) did not work

and how do i do the opposite as well? eg. z{1,1}(1)

A portion of z, z value is random for each cell.
Columns 1296 through 1300

      [1×23 double]    [1×23 double]    [1×29 double]    [1×23 double]    [1×25 double]
      [1×27 double]    [1×25 double]    [1×25 double]    [1×25 double]    [1×27 double]
      [1×21 double]    [1×25 double]    [1×27 double]    [1×27 double]    [1×25 double]
      [1×27 double]    [1×29 double]    [1×29 double]    [1×25 double]    [1×23 double]
      [1×27 double]    [1×25 double]    [1×23 double]    [1×27 double]    [1×27 double]
      [1×27 double]    [1×27 double]    [1×23 double]    [1×21 double]    [1×23 double]
      [1×25 double]    [1×29 double]    [1×27 double]    [1×27 double]    [1×27 double]
      [1×27 double]    [1×21 double]    [1×21 double]    [1×29 double]    [1×27 double]
      [1×25 double]    [1×25 double]    [1×25 double]    [1×21 double]    [1×27 double]
      [1×23 double]    [1×25 double]    [1×25 double]    [1×25 double]    [1×23 double]

Answer 1

[Walter Roberson]

cellfun( @(Z) find(abs(Z-z_position)<intvl), z, 'uniform', 0)

the output will be a cell array each element of which is the list of indices for the corresponding cell in z.

[Joseph Lee]

Thanks! It works, how do i use it to find the corresponding values in another cell M which is exactly the same size, 10x1300 cell of same size as z. E.g I am finding the minimum of M for z=1,

index=cellfun( @(Z) find(abs(Z-1)<0.005), z, 'uniform', 0);
          min(M(index)); < how should i change this part?

[Walter Roberson]

cellfun(@(IDX) min(M(IDX)), index, 'uniform', 0)

[Joseph Lee]

Thanks!

[Joseph Lee]

Hi, i got an error which says Error using min Invalid data type. First argument must be numeric or logical. How do i fix this? Does this have something to do with the zeros?

index results Columns 1297 through 1300

    [1×0 double]    [1×0 double]    [1×0 double]    [1×0 double]
    [1×0 double]    [1×0 double]    [1×0 double]    [1×0 double]
    [        25]    [1×2 double]    [1×2 double]    [1×2 double]
    [1×2 double]    [1×2 double]    [1×2 double]    [1×2 double]
    [1×2 double]    [1×2 double]    [1×2 double]    [1×2 double]
    [1×0 double]    [1×0 double]    [1×2 double]    [1×2 double]
    [1×0 double]    [1×0 double]    [1×0 double]    [1×0 double]
    [1×0 double]    [1×0 double]    [1×0 double]    [1×0 double]
    [1×0 double]    [1×0 double]    [1×0 double]    [1×0 double]
    [1×0 double]    [1×0 double]    [1×0 double]    [1×0 double]

I have posted another question with regards to this

[Walter Roberson]

cellfun(@(m, IDX) min(m(IDX)), M, index, 'uniform', 0)

[Joseph Lee]

I got another error :Subscripted assignment dimension mismatch.

I have checked the dimensions, they are both 10x1300 cell arrays. Is it something else I am missing?

[Joseph Lee]

I think i know why, the minimum im looking for is not for each cell array but for all the cells, the result should give only one single value which i am storing into a matrix while increasing the find(abs(Z-1)<0.005) to find(abs(Z-2)<0.005) and so on

[Walter Roberson]

Do you need to know just the value out of all of the M, or do you need to know which cell of M it came from and the index inside that cell?

[Joseph Lee]

Only the min out of all the M, one single value.