# proof if value is greatest of a range of Values

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Jonas Maurer on 12 Dec 2017
Commented: KL on 13 Dec 2017
Dear all,
i have got following problem. I am very thankful for any answer! See m+/-50: I want to refer to a range of rows and see if for example cell(230,1) has got the greatest value of all 50 cells above and below it (180:280,1). I tried with: (m-50:m+50,1) but it doesn´t work. Can u help me?
if true
for m=1:e-a
if X(m,3)==1 && X(m,1)>=X(m+/-50,1)
X(m,5)=1;
else
disp('zero')
end
end

KL on 12 Dec 2017
Edited: KL on 12 Dec 2017
Yes, you could do that but I'm unsure if you'd really need a for-loop. If you could explain your real intentions, the actual solution maybe simpler. I'm gonna assume you know you'd need it only this way.
range = 50;
sz = size(X);
for k=1:sz(1)
if X(k)>=X(max(1,k-range):min(k+range,sz(1)))
X(k)
else
end
end
Here I've considered to be a vector(you could simply add the second index when you write it for a matrix) and I check if the k-th element is greater or equal to the biggest of the elements within the given range. I have used max and min, so we cover the range where we have less elements on either side.
KL on 13 Dec 2017
Very good, yeah, that's the idea. If you want to store words, you cannot use a numeric matrix, obviously. Alternative is to use a cell array or a table. They both help you store different data types together in a matrix like format but latter would be my suggestion.