two for Nested Loops

How i can sum the third column to get the average over each 24 values of the second coloumn?

2 Comments

KL
KL on 14 Dec 2017
Edited: KL on 14 Dec 2017
sounds more like making daily sum from hourly data. Use a timetable!
KL
Yes, it is the daily sum from hourly data. but How the time table can be used?

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Answers (6)

Jos (10584)
Jos (10584) on 14 Dec 2017
Edited: Jos (10584) on 14 Dec 2017
Your question is a little unclear. Do you want to sum all values of the third row when the second row equals 0, equals 1, etc, so you end up with 24 summed values? That is easy:
A = xlsread('average24');
S = accumarray(A(:,2)+1, A(:,3), [24,1], @mean)
% S(k) is the average of all values of A(:,3) when A(:,2) equals (k-1)

1 Comment

you want the average, answer corrected! :)

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Jan
Jan on 14 Dec 2017
Edited: Jan on 14 Dec 2017
Maybe
A = xlsread('average24');
% Average over blocks of 24 values:
S1 = mean(reshape(A(:, 3), 24, []), 1);
% Or average over all values belonging to 0, 1, 2, ...:
S2 = mean(reshape(A(:, 3), 24, []), 2);
KL
KL on 14 Dec 2017
Edited: KL on 15 Dec 2017
An example with timetable,
EDITED
%import data
data = readtable('actual data.txt');
%create a proper datetime column
data.Timestamp = datetime(cell2mat(data{:,[1 2]}),'InputFormat','yyyy.MM.ddHH:mm');
%keep only datetime and measurements
data = data(:, [end 3]);
%create timetable
TT = table2timetable(data(:,2),'rowtimes',data.Timestamp);
%calculate daily mean
TT_mean = retime(TT,'daily','mean');
ahmad Saad
ahmad Saad on 14 Dec 2017

0 votes

I'm very grateful for all. i'll check the answers and feek back
the answers are really helpfull
thanks again
ahmad Saad
ahmad Saad on 15 Dec 2017

0 votes

This the actual data
from 1/10/2017 to 30/11/2017 the output should have 61 values

4 Comments

KL
KL on 15 Dec 2017
check my edited answer!
First, thanks for your help
it seems that there is a error with respect to second line, i get: variable index exceeds table dimension
(i put the data in an excel file)
KL
KL on 15 Dec 2017
Edited: KL on 15 Dec 2017
The answer I gave you works on your text file. I tested it before posting it here!
This is the output
TT_mean =
61×1 timetable
Time Var3
__________ ______
2017-10-01 9383.2
2017-10-02 9388.9
2017-10-03 9420.8
2017-10-04 9449.3
2017-10-05 9463
2017-10-06 9456.5
2017-10-07 9406.2
2017-10-08 9364.3
2017-10-09 9386.4
2017-10-10 9440.3
...
KL
OK
i'll try again and feedback; thanks for your kind attention

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ahmad Saad
ahmad Saad on 15 Dec 2017

0 votes

Birdman
deep thanks, it works fine, thanks : Birdman

Asked:

on 14 Dec 2017

Commented:

on 15 Dec 2017

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