Index exceeds matrix dimensions problem with this code below :-
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hannibal lecter
on 7 Jan 2018
Answered: Walter Roberson
on 7 Jan 2018
c =
1 1 1 6
2 4 2 16
-1 5 -4 -3
N = length(c);
tol= 1e-6;
for ii=1:N-1
for jj=ii+1:N
if abs(c(jj,ii))> tol
fac=c(ii,ii) / c(jj,ii);
c(jj,:) = fac*c(jj,:) - c(ii,:);
end
end
end
how to solve this problem? that code for Gauss elimination when I press enter it appear " Index exceeds matrix dimensions "
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Accepted Answer
ANKUR KUMAR
on 7 Jan 2018
c =[1 1 1 6; 2 4 2 16; -1 5 -4 -3]
N = size(c,1)
M=size(c,2)
tol= 1e-6;
for ii=1:M-1
ii
for jj=ii+1:N
jj
if abs(c(jj,ii))> tol
fac=c(ii,ii) / c(jj,ii);
c(jj,:) = fac*c(jj,:) - c(ii,:);
end
end
end
Instead of writing length(c), you should to define the size along first and second dimension of matrix, i.e. define the number of row and columns of matrix.
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More Answers (1)
Walter Roberson
on 7 Jan 2018
length() of a 3 x 4 array is 4. length() is not the number of rows: length() is defined as:
- 0 if any dimension of the array is 0; or
- max() of size() of the array otherwise.
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