Index exceeds matrix dimensions problem with this code below :-

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c =
1 1 1 6
2 4 2 16
-1 5 -4 -3
N = length(c);
tol= 1e-6;
for ii=1:N-1
for jj=ii+1:N
if abs(c(jj,ii))> tol
fac=c(ii,ii) / c(jj,ii);
c(jj,:) = fac*c(jj,:) - c(ii,:);
end
end
end
how to solve this problem? that code for Gauss elimination when I press enter it appear " Index exceeds matrix dimensions "

Accepted Answer

ANKUR KUMAR
ANKUR KUMAR on 7 Jan 2018
c =[1 1 1 6; 2 4 2 16; -1 5 -4 -3]
N = size(c,1)
M=size(c,2)
tol= 1e-6;
for ii=1:M-1
ii
for jj=ii+1:N
jj
if abs(c(jj,ii))> tol
fac=c(ii,ii) / c(jj,ii);
c(jj,:) = fac*c(jj,:) - c(ii,:);
end
end
end
Instead of writing length(c), you should to define the size along first and second dimension of matrix, i.e. define the number of row and columns of matrix.

More Answers (1)

Walter Roberson
Walter Roberson on 7 Jan 2018
length() of a 3 x 4 array is 4. length() is not the number of rows: length() is defined as:
  • 0 if any dimension of the array is 0; or
  • max() of size() of the array otherwise.

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