throws to get yahtzee!?

I have a schoolproject where I'm about to create a function that shows how many throws u need to get a yatzy with five dices.

I think my code works to get yatzy one time, but when I try to do it 50000 times and take out the average value (suppost to be 11~) I get 18 every time.

Can anyone see whats wrong? The problem might be that my function counts every dice as a throw, when its suppost to count for example 3 dices as one throw if I "want" the function to throw all 3 at ones, just like u do in yatzy if u know the game. If u have any questions about names etc, just let me know!

Anyway, here is my code so far:

function yatzy=yatz(n)

MC = 0;

for z=1:50000;

i=0;
count=1;

for i = 1:n;

      kast(i)=floor(rand*6);

end

sort(kast);

[Y,I]= mode(kast);

A = ones(1,I);

B = Y*A;

dices = 5-I;

while dices ~= 0;

      O = floor(rand*6);
      if O==Y;
          dices = dices-1;

      end
      count=count+1;
  end
  korv=ones(1,n)*Y;

MC = MC+count;

end

medel = MC/50000;

medel

end

Answer 1

[Jan]

At first I'd remove the unnecessary code to reduce the confusion. E.g. "i = 0" has no effect, "sort(kast)" neither, "A = ones(1,I); B = Y*A;" is not required and "korv=ones(1,n)*Y;" wastes time only also.

Then the game, that I know and which is called "Yatzee", allowed throwing the dice 3 times only, while you throw them until you have 5 equal values. So I guess, that the game you have programmed, and the game, which leads to 11, have different rules.