interpolating Sample data to finer increment

3 views (last 30 days)
Hello,
What I have is a 3D set of point X, Y and Z(Weights) and I want to be able to interpolate the Z data to finer intervals in the X and Y direction. Say X from -17.5, 17.5 in 0.5 steps and Y 15 to -15 in 0.25 step.
------- Zone -17.5 0 17.5 15 0.6 0.8 0.6 0 0.7 1 0.7 15 0.6 0.8 0.6 -------
[Weights] = [0.6 0.8 0.6; 0.7 1.0 0.7; 0.6 0.8 0.6];
[X] = [-17.5,0,17.5];
[Y] = [-15, 0, 15];
figure
surf(X,Y,Weights)
title('Original Sampling');

Accepted Answer

Thorsten
Thorsten on 17 Jan 2018
Vq = interp2(X,Y',Weights, -17.5:0.5:17.5, (-15:0.25:15)');

More Answers (1)

Michael
Michael on 17 Jan 2018
Thanks
Both of the following lines did solve my issue; however, I am not sure what the ' does, In this example exactly what does the prime symbol ' achieve?
Vq = interp2(X,Y,Weights, -17.5:0.5:17.5, (-15:0.25:15)', 'cubic'); Vq = interp2(X,Y,Weights', -17.5:0.5:17.5, (-15:0.25:15)', 'cubic');
  1 Comment
Thorsten
Thorsten on 18 Jan 2018
The ' transposes the vector from a row to a column vector. From the help of interp2:
Xq can be a row vector, in which case it specifies a matrix with
constant columns. Similarly, Yq can be a column vector and it
specifies a matrix with constant rows.
Not that if you transpose your Weights you will have a different solution.

Sign in to comment.

Categories

Find more on Interpolation in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!