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what is the function of (sub2ind)

Asked by Alaaeldin Mohamed on 3 Feb 2018
Latest activity Edited by per isakson
on 8 Feb 2018
Accepted Answer by Jan
a = eval(['sub2ind(20.*ones(1,20)'',20,1' ');'])

  1 Comment

More to the point, is why anyone in their right mind would ever want to write that code? A mess, with absolutely no good purpose.
Far better would be the simple:
a = 20;

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1 Answer

Jan
Answer by Jan
on 4 Feb 2018
Edited by Jan
on 5 Feb 2018
 Accepted Answer

The line is extreme nonsense. As John has said already, all it does is assigning a=20 .
Without the confusing eval, it is:
a = sub2ind(20 .* ones(1,20)', 20, 1)
ones(1,20)' is the same as ones(20,1). If you multiply this by 20, you get a [20 x 1] column vector containing 20s. Using sub2ind interprets this vector as the size of an array (an extremely huge array with 20^20 elements, but it is not created explicitly). Now the "linear index" is determined for the element in the 20th row and 1st column. The linear index is useful to enumerate all elements of an array using one index. See e.g.:
a = rand(2, 3)
a(1:6)
The linear index is applied in columnwise order, and in the first row it equals the column index. As long as the first dimension has >= k elements, sub2ind(S, k, 1) replies k.
Hiding this hilarious code in an eval command seems to be a pure obfuscation: Useless code to impede the reading. Contact the author and buy him a cup of coffee.

  1 Comment

Thank you for your excellent explaination

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