Saving the last value of a loop that will run 100 times

I have a function x that is dependent on a random variable s, where s =randn(1,1) the function x=x+s , where x will be replaced by the new value everytime the loop runs i need to create a loop script that when x is less/equal to -10 or more/equal to 10, it will stop and calculate how many times the loop has ran. I then need to run this loop in a loop 100 times and calculate the average number of times the loop ran to hit the 10/-10 condition in a total of 100 times. My script looks like this with alot missing:

x=0;
step=0;
while (x<10)&&(x>-10)
    s=randn(1,1);
    x=x+s;
    step=step+1
end

Answer 1

[Torsten]

step = zeros(100,1);
for k=1:100
  x=0;
  step_actual=0;
  while (x<10)&&(x>-10)
    step_actual = step_actual+1;
    s=randn(1,1);
    x=x+s;
  end
  step(k)=step_actual;
end 
step_mean = mean(step);

[manfred chng]

Thank you! Its working well!

Answer 2

[KSSV]

x=0;
step=0;
X = zeros([],1) ;
while (x<10)&&(x>-10)
    s=randn(1,1);
    x=x+s;   
    step=step+1
    X(step) = x ;
end

x is saved in X.

[manfred chng]

Hi thankyou! But is it possible for example, my first run on the loop returns me a final value of step=200 and 100 on my 2nd run. i want to store 200 and 100 in a matrix [200,100, the remaining values of 98 runs]. How do i do that?