how can split image to 4 parts using "reshape" or using another way?

how can split image to 4 parts using "reshape" or using another way?

Answer 1

[John D'Errico]

Why not try something? That is how you will learn.

A = rand(10,10)
A =
      0.93614      0.13657      0.90563       0.5726      0.84819      0.67039      0.88059      0.60703      0.70625      0.51732
      0.65876      0.21378      0.65182      0.38672     0.071682       0.4315      0.46093     0.053151      0.11428      0.21982
      0.74794      0.21783      0.55094     0.085353      0.73923      0.34301      0.24875      0.59034      0.62061      0.38731
      0.29529      0.14848     0.085495       0.3939      0.30351      0.61554      0.37059      0.26615       0.9813      0.66854
      0.68423       0.6687      0.85758     0.058756      0.14468    0.0059446      0.68537      0.58939      0.36382      0.22756
      0.20548      0.12054       0.5337      0.44348      0.47234      0.50325      0.32803      0.63827      0.94148       0.4208
      0.77899      0.84029      0.53184      0.32736     0.021976      0.74268      0.80725       0.4474      0.28855      0.55414
      0.56198      0.66423     0.093623      0.53036      0.25132      0.61766      0.95857      0.47626      0.57313      0.76301
      0.42388      0.80682      0.17905      0.21329      0.42847      0.85672      0.24577      0.91463      0.32361      0.16648
     0.046974     0.085508      0.73136      0.96149       0.5751       0.9539      0.51691      0.69254      0.99483       0.8542

permute(reshape(A,[10/2,2,10/2,2]),[1 3 2 4])
ans(:,:,1,1) =
      0.93614      0.13657      0.90563       0.5726      0.84819
      0.65876      0.21378      0.65182      0.38672     0.071682
      0.74794      0.21783      0.55094     0.085353      0.73923
      0.29529      0.14848     0.085495       0.3939      0.30351
      0.68423       0.6687      0.85758     0.058756      0.14468
ans(:,:,2,1) =
      0.20548      0.12054       0.5337      0.44348      0.47234
      0.77899      0.84029      0.53184      0.32736     0.021976
      0.56198      0.66423     0.093623      0.53036      0.25132
      0.42388      0.80682      0.17905      0.21329      0.42847
     0.046974     0.085508      0.73136      0.96149       0.5751
ans(:,:,1,2) =
      0.67039      0.88059      0.60703      0.70625      0.51732
       0.4315      0.46093     0.053151      0.11428      0.21982
      0.34301      0.24875      0.59034      0.62061      0.38731
      0.61554      0.37059      0.26615       0.9813      0.66854
    0.0059446      0.68537      0.58939      0.36382      0.22756
ans(:,:,2,2) =
      0.50325      0.32803      0.63827      0.94148       0.4208
      0.74268      0.80725       0.4474      0.28855      0.55414
      0.61766      0.95857      0.47626      0.57313      0.76301
      0.85672      0.24577      0.91463      0.32361      0.16648
       0.9539      0.51691      0.69254      0.99483       0.8542

Answer 2

[Image Analyst]

How about indexing?

[rows, columns, numColorChannels] = size(yourImage);
middleRow = floor(rows/2);
middleCol = floop(columns/2);
upperLeftImage = yourImage(1:middleRow, 1:middleCol, :);
upperRightImage = yourImage(1:middleRow, middleCol+1:end, :);
lowerLeftImage = yourImage(middleRow+1:end, 1:middleCol, :);
lowerRightImage = yourImage(middleRow+1:end, middleCol+1:end, :);