Calculate velocity from position and time

I have to write a program to calculate the velocity given position and time in two arrays.

Answer 1

[KSSV]

pos = rand(100,1) ;
t = 1:100 ;
v = zeros(length(t)-1,1) ;
for i = 1:length(t)-1
    v(i) = (pos(i+1)-pos(i))/(t(i+1)-t(i)) ;
end

[James Tursa]

Please don't supply complete answers to homework problems ...

[Kelly Harmison]

Thanks! I wrote a similar code but I was saving the loop values in v instead of v(i) This was very helpful!

[alper yeldan]

There is a way to solve it withouth for loop which gives the same solution.

vel = diff(pos)./diff(t);

You can compare them

pos = rand(100,1) ;
t = 1:100 ;
v = zeros(length(t)-1,1) ;
for i = 1:length(t)-1
    v(i) = (pos(i+1)-pos(i))/(t(i+1)-t(i)) ;
end
vel = diff(pos)./diff(t);

figure;
hold on;
plot(t(1:end-1),v,'--r+');
plot(t(1:end-1),vel,'bo');

Answer 2

[Arms Diether Reyes]

The driver of a car wishes to pass a truck that is traveling at a constant speed of 20.0 m/s. Initially, the car is also traveling at 20.0m/s and its front bumper is 24.0 m behind the truck’s rear bumper. The car accelerates at a constant 0.0600 m/s^2, then pulls back into the truck’s lane when the rear of the car is 26.0 m ahead of the front of the truck. The car is 4.5 m long and the truck is 21.0 m long. (a) How much time is required for the car to pass the truck? (b) What distance does the car travel during this time? (c) What is the final speed of the car?