how to copy the segmented image in to single variable?

how to copy the segmented image in to single variable?

test=imread(fname);
imData=reshape(test,[],1);
imData=double(imData);
[IDX nn obj]=fcm(imData,4);

Answer 1

[Image Analyst]

I don't have the Fuzzy Logic Toolbox, but if it gives you a vector, you can reshape it

[rows, columns, numberOfColorChannels] = size(test);
classifiedImage = reshape(IDX, rows, columns];
imshow(classifiedImage, []);

[Melaku Eneayehu]

thank you but i already try this one but i got this error Error using reshape To RESHAPE the number of elements must not change.

Error in fuzzy (line 16) classifiedImage = reshape(IDX, rows, columns);

[Image Analyst]

What are the values of rows, columns, numberOfColorChannels? If it's color, you may need to take that into account.

What is the size of IDX?

>> whos IDX

[Melaku Eneayehu]

Images are gray scale and IDX is

Name      Size            Bytes  Class     Attributes

    IDX       4x1                32  double  
i also try mat2gray but it doesn't work

[Image Analyst]

You need to use nn. (This is why it's good to name variables sensibly.)

https://www.mathworks.com/help/fuzzy/fcm.html?s_tid=srchtitle#inputarg_data

[centers,U,objFunc] = fcm(___)

U: Fuzzy partition matrix, returned as a matrix with Nc rows and Nd columns. Element U(i,j) indicates the degree of membership of the jth data point in the ith cluster. For a given data point, the sum of the membership values for all clusters is one.

So you need to scan U and find out what column the max value is in. That's what class it thinks that pixel is in. Something like (untested because I don't have that toolbox):

classifiedImage = zeros(rows, columns);
for k = 1 : length(U)
    % For every pixel...
    [~, col] = max(U(k, :));
    outputImage(k) = col;
end
outputImage = reshape(outputImage, rows, columns);