Execute/load multiple .m file in single main .m file

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Hi, recently I build multiple program which each of them has their own m file. For example, there are a.m, b.m and c.m. What I want to do is to execute each of the program in single main program in .m (Let say main.m). However, I could not achieved the solution yet.
%%%%Main program %%%%
run(a.m);
run(b.m);
run(c.m);
The result coming out is:
Undefined variable "a" or class "a.m".
Each m file has coding that will give out output in array or cell. Is there more effective solution that enable me to execute m coding from other m file in my main m file? Perhaps on what I need is retype all coding from all separate file and write it into single main.m?
Thank you

Accepted Answer

Birdman
Birdman on 19 Mar 2018
Edited: Birdman on 19 Mar 2018
Just simply write
a
b
c
which are the names of your m files.
  1 Comment
Muhammad Bariq Azmi
Muhammad Bariq Azmi on 19 Mar 2018
Thanks! Never thought that I'm actually overthinking despite the solution is much more direct to the point

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More Answers (1)

Jan
Jan on 19 Mar 2018
The problem is, that in run(a.m) "a.m" is interpreted as the field "m" of the struct "a". Therefore you get this message, which is clear actually:
Undefined variable "a" or class "a.m"
You want "a.m" to be a char vector containing the name of the script instead. Then you need quotes:
run('a.m')
Using the direct form:
a
is much easier, but with the run() command you can define the path of the script also.
  5 Comments
Jan
Jan on 15 Dec 2021
Does this have a realtion to the question of this thread? If not, ask a new question, please.
Maybe the .m-files are scripts starting with a clear command. Then all former results are deleted.

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