Plotting every iteration of a while loop with multiple if statements

I have a while loop that has 3 if statements within it. For example while x>0 && x<5 and 3 if statements solving for y with different formulas within that range of 0-5. I need to plot every iteration of that range and cannot figure out how to do so.

Thanks!

[Birdman]

Share your code.

[Sean Sullivan]

x = 0.5;
 while x>0 && x<6
 x = x+0.5; 
if x <4 
syms y 
eqn = y==2*x; 
y = solve(eqn,y) 
end 
if x>4
 syms y 
eqn = y==0.5*x; 
y = solve(eqn,y) 
end 
if x == 4
 syms y 
eqn = y==5*x;
 y = solve(eqn,y)
 end 
end

[VBBV]

x = 0.5;
 while x>0 && x<6
     x = x+0.5; 
    if x<4 
    syms y 
        eqn = y==2*x; 
        y = solve(eqn,y);
        plot(x,y,'bo','MarkerFaceColor','b')
        hold on
    end 
    if x>4
     syms y 
         eqn = y==0.5*x; 
         y = solve(eqn,y) 
         plot(x,y,'ro','MarkerFaceColor','r')
     hold on
    end 
    if strcmp(x,4)
     syms y 
         eqn = y==5*x;
         y = solve(eqn,y)
         plot(x,y,'yo','MarkerFaceColor','y')
     end 
end

y = 

y = 

y = 

y = 

3

Answer 1

[Ameer Hamza]

From our code in the comment , it appears that you don't need solve() function. You just have one equation and you already know the value of independent variable x. You can write your code as

l = line;
l.XData = [];
l.YData = [];

x = 0.5;
while x>0 && x<6
    x = x+0.5;
    if x <4
        y = 2*x;
        l.XData = [l.XData x];
        l.YData = [l.YData y];
    end
    if x>4
        y = 0.5*x;
        l.XData = [l.XData x];
        l.YData = [l.YData y];
    end
    if x == 4
        y = 5*x;
        l.XData = [l.XData x];
        l.YData = [l.YData y];
    end
end

This will also plot values of x and y.