How to fix the error code 'Subscripted assignment dimension mismatch.'

Here is the code that I'm getting the error:

for z=1:length(X)

V(z)=[X(z):Y];

end

where X is a 1x81 matrix and Y is an integer

Answer 1

[Ameer Hamza]

The right side of the assignment is an array, you are trying to assign to one vector element V(z). This is not possible with matrices in MATLAB. You will need cell array for this,

V = cell(1, length(X));
for z=1:length(X)
  V{z}=[X(z):Y];
end

[Davis Storey]

Is there a way to do this without using cell arrays? If not how to u divide a matrix by a cell array?

[Ameer Hamza]

Can you show your data? How do you want to divide. You can convert cell array to matrix using cell2mat() but that will only work if all elements of V have same length.

[Walter Roberson]

In order to do it without using cell arrays, you would need to pad the array so that all of the rows were the same length.

What is the matrix that is to be divided? And are you wanting to do element-by-element division or to do the equivalent of the inverse of algebraic matrix multiplication? Are you trying to do something like solve a sparse system of linear equations?

Answer 2

[Davis Storey]

after finding v, I need to input it into another for loop:

for k=1:length(v)

      p34{k}=P*(X./v(k)).^constant;
  end

[Walter Roberson]

No, you cannot expect to do that. X is a fixed size vector, but v is a variable sized vector unless all of the entries in X are the same. When you X ./ a variable-sized subset of X, you are going to have size inconsistencies. This does not make sense unless you want to divide every element of X by every element of v, making a 2D matrix for each p34 element.