Getting all the real solutions of a 12 variable 12 non-polynomial equations using vpasolve()

The equation which i want to solve looks like this:
A(y)=(a6*x^5+a5*x^4+a4*x^3+a3*x^2+a2*x+a1)*[log(28/B(y)/(b6*x^5+b5*x^4+b4*x^3+b3*x^2+b2*x+b1))]
where, A(y) and B(y) are real value functions of 'y'
Here, for 12 different sets of(x,y) we are going to get 12 sets of equations. From those equations I want to find the real solutions for a1,a2,a3,a4,a5,a6,b1,b2,b3,b4,b5,b6
I want to get all the real solutions of them. I am getting only a single set of solution for them which is imaginary. I'm only interested in real solutions.
So, If there is any way to solve this problem then please help.

4 Comments

vpasolve() will only give all of the solutions of polynomial equations.
It would be much easier to test if we had some representative data to work with... otherwise we could spend a long time lost trying to find appropriate data ranges.
I am only interested in real solutions but I am getting imaginary... Is it possible to get at least one real solution set....that will be enough.
No, it is not possible to get any solutions when so little information is available. To get any further we need to know at least the possible range of values for x and corresponding y and for A(y) and B(y) . For testing period should be I be using, for example, random numbers in the range -10000 to +10000 for everything? Because of the log(), negative B could be a problem unless x is also negative or b6 is negative (thereby making the expression inside the log() positive.)
these are the equations with the values of x and y (Now i reduced them to 10 equations for now and want the closest real possible solutions if not exact) http://textuploader.com/dfe39 ...Yeah you are correct, B should also be positive otherwise it will result in imaginary outcomes

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R2017b

Asked:

on 24 May 2018

Edited:

on 26 May 2018

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