Extract Data from Timetable
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Hi, i have a daytime Matrix and i also have a second timetable of 2 columns (first Time, second Data) of dates from which i want to extract for each daytime of the first Matrix the Data that refers to this Date fromthe second one!
Is there an easy way, without using a for loop, to do so?
10 Comments
dpb
on 2 Jun 2018
Yes
Ioannis Tsikriteas
on 2 Jun 2018
Paolo
on 2 Jun 2018
Can you share the code for what you have tried so far?
Ioannis Tsikriteas
on 2 Jun 2018
Paolo
on 2 Jun 2018
An example:
A datetime matrix:
daytimemat = datetime(['13/04/2018';'25/04/2018';'28/04/2018'],'Format','dd/MM/yyyy');
A timetable with dates and data.
tt = timetable(datetime({'13/04/2018';'25/04/2018';'26/04/2018';'28/04/2018'}), [37.3;39.1;42.3;21]);
The following command:
tt.Var1(tt.Time(daytimemat))
outputs :
37.3000
39.1000
21.0000
which is the data contained in the timetable tt corresponding to the dates in daytimemat array.
Does this help?
Ioannis Tsikriteas
on 2 Jun 2018
Edited: Ioannis Tsikriteas
on 2 Jun 2018
@Ioannis, I have submitted an answer for the original question. If that solved the problem, please accept it so it will be easily visible to other users (rather than having the solution in the comment section).
As for your second question, I was unable to replicate the problem.
x = datetime('08-Jul-2012 00:19:59','Format','dd-MMM-yyyy hh:mm:ss');
x = addtodate(datenum(x),-1,'year');
datestr(x)
The output is:
08-Jul-2011 00:19:59
Ioannis Tsikriteas
on 2 Jun 2018
Edited: Ioannis Tsikriteas
on 2 Jun 2018
Peter Perkins
on 4 Jun 2018
Ioannis, I'm pretty sure every loop in your code is unnecessary. For example:
y = NaT(somePreallocationSize);
i = isbetween(x-calyears(1),down,up);
y(i,5) = t(i,5);
I can't really follow everything that's in your code, but that's the idea. This will run MUCH faster and is much simpler to write and maintain.
Ioannis Tsikriteas
on 4 Jun 2018
Accepted Answer
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