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why does simulink use the transfer function to simulate the step response?

Asked by Giuseppe Alfieri on 15 Jun 2018 at 6:48
Latest activity Commented on by Giuseppe Alfieri on 15 Jun 2018 at 10:53

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Both of these are separate blocks. Simulink does not "use" the transfer function, the model which you have designed or referred to here passes the output of the step function to the transfer function.

I'm sorry but i didn't explain myself well. My question was because the output of transfer function's block is the step response in the time domain and not in Laplace one?

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