Why I am getting the error message:Assignment has more non-singleton rhs dimensions than non-singleton subscripts

syms tmv; tdcvv=[ 1.7691180562790619335090624118428, 3.7203521516231003235052331604841, 4.2549397326879975357442412372052; 1.8728284259647972559033795104949, 4.0675421128150192508477208506903, 5.0616967785172204893339442877428; 2.1175654748328456634231199033899, 3.1758086461927840904807328442577, 3.7653737399696897254758169563108]; S=40; C=60; a0=1.993; a1=0.002; a2=0.015; b0=38.086; b1=-0.176; b2=-0.633; c0=10.720; c1=1.256; c2=1.522; a=a0+a1.*S+a2.*C; b=b0+b1.*S+b2.*C; c=c0+c1.*S+c2.*C; eqs=a+b.*tmv+c.*tmv.^2; teqs=eqs==tdcvv; teqsd=vpa(teqs); tmvVV=sym('tmvVV',[3 3]); tic for i=1:3 for j=1:3 tmvVV(i,j)=vpasolve(teqsd(i,j),tmv); end end

Answer 1

[Dennis]

tmvVV(i,j)=vpasolve(teqsd(i,j),tmv);

This line returns 2 values, but tmvVV(i,j) has only 1 field. Adding a third dimension tmvVV(i,j,:) or using cells should fix your problem.

    syms tmv; 
    tdcvv=[ 1.7691180562790619335090624118428, 3.7203521516231003235052331604841, 4.2549397326879975357442412372052; 1.8728284259647972559033795104949, 4.0675421128150192508477208506903, 5.0616967785172204893339442877428; 2.1175654748328456634231199033899, 3.1758086461927840904807328442577, 3.7653737399696897254758169563108];
    S=40; C=60; a0=1.993; a1=0.002; a2=0.015; b0=38.086; b1=-0.176; b2=-0.633; c0=10.720; c1=1.256; c2=1.522; a=a0+a1.*S+a2.*C; b=b0+b1.*S+b2.*C; c=c0+c1.*S+c2.*C; eqs=a+b.*tmv+c.*tmv.^2; teqs=eqs==tdcvv; 
    teqsd=vpa(teqs);
    tmvVV=sym('tmvVV',[3 3 2]);
    for i=1:3
        for j=1:3
            tmvVV(i,j,:)=vpasolve(teqsd(i,j),tmv); 
        end
    end

[Sandra Maria Cherian]

Now it is working. Thank you Dennis