From a vector to a 3D array

I would like to create a 3D array from a vector. As an example, the size of the could be 6x5x4 and the vector is 120x1.

I tried to reshape function but the elements order of the array "result" are not correct

I copied the solution that I should obtain for the array result for a (:,:,1)

     % result(:,:,1) =

Columns 1 through 4

         0.353158571222071          0.73172238565867         0.188955015032545        0.0811257688657853
         0.821194040197959         0.647745963136307         0.686775433365315          0.92938597096873
        0.0154034376515551         0.450923706430945          0.18351115573727         0.775712678608402
        0.0430238016578078         0.547008892286345         0.368484596490336         0.486791632403172
         0.168990029462704         0.296320805607773          0.62561856072969         0.435858588580919
         0.649115474956452         0.744692807074156         0.780227435151377         0.446783749429806

Column 5

         0.306349472016557
         0.508508655381127
          0.51077156417211
         0.817627708322262
         0.794831416883453
         0.644318130193692

I attached the vector file.

[Stephen23]

"I tried to reshape function but the elements order of the array "result" are not correct"

Sure. But you did not tell us what the "correct" order should be.

Answer 1

[Stephen23]

A simple reshape gives the exact order that you request:

>> mat = reshape(vector,[6,5,4])
mat(:,:,1) =
  0.353158571222071  0.73172238565867  0.188955015032545  0.08112576886578526  0.306349472016557
  0.8211940401979591  0.6477459631363069  0.686775433365315  0.92938597096873  0.508508655381127
  0.01540343765155505  0.450923706430945  0.18351115573727  0.775712678608402  0.51077156417211
  0.04302380165780784  0.547008892286345  0.368484596490336  0.486791632403172  0.8176277083222619
  0.168990029462704  0.296320805607773  0.62561856072969  0.435858588580919  0.794831416883453
  0.6491154749564521  0.744692807074156  0.780227435151377  0.446783749429806  0.644318130193692
mat(:,:,2) =
  0.378609382660268  0.550156342898422  0.230488160211558  0.435698684103899  0.979748378356085
  0.811580458282477  0.622475086001227  0.8443087926953891  0.311102286650413  0.438869973126103
  0.532825588799455  0.587044704531417  0.194764289567049  0.923379642103244  0.111119223440599
  0.350727103576883  0.207742292733028  0.225921780972399  0.430207391329584  0.258064695912067
  0.939001561999887  0.301246330279491  0.170708047147859  0.184816320124136  0.408719846112552
  0.875942811492984  0.470923348517591  0.227664297816554  0.904880968679893  0.594896074008614
mat(:,:,3) =
  0.262211747780845  0.318778301925882  0.02922027756214629  0.458848828179931  0.62406008817369
  0.602843089382083  0.424166759713807  0.928854139478045  0.963088539286913  0.679135540865748
  0.7112157804336831  0.507858284661118  0.730330862855453  0.546805718738968  0.395515215668593
  0.22174673401724  0.08551579709004398  0.488608973803579  0.5211358308040011  0.367436648544477
  0.117417650855806  0.262482234698333  0.578525061023439  0.231594386708524  0.987982003161633
  0.296675873218327  0.801014622769739  0.237283579771521  0.488897743920167  0.03773886623955214
mat(:,:,4) =
  0.885168008202475  0.679727951377338  0.779051723231275  0.197809826685929  0.609866648422558
  0.913286827639239  0.13655313735537  0.715037078400694  0.03054094630463666  0.617666389588455
  0.796183873585212  0.72122749858174  0.903720560556316  0.744074260367462  0.859442305646212
  0.0987122786555743  0.106761861607241  0.890922504330789  0.500022435590201  0.805489424529686
  0.261871183870716  0.6537573486685599  0.334163052737496  0.47992214114606  0.576721515614685
  0.335356839962797  0.49417393663927  0.698745832334794  0.904722238067363  0.182922469414914

And checking:

"See that for (2,1,1) the result that I need is 0.821194040197959"

>> mat(2,1,1)
ans = 0.8211940401979591

Answer 2

[trey]

@Stephen Cobeldick, thank you for your quick replay.

I copied the results that I have to obtain. The order that you propose is not the correct that I need.

See that for (2,1,1) the result that I need is 0.821194040197959 and in the code you proposed is 0.649115

   % result(:,:,1) =
  Columns 1 through 4
           0.353158571222071          0.73172238565867         0.188955015032545      0.0811257688657853
           0.821194040197959         0.647745963136307         0.686775433365315          0.92938597096873
          0.0154034376515551         0.450923706430945          0.18351115573727         0.775712678608402
          0.0430238016578078         0.547008892286345         0.368484596490336         0.486791632403172
           0.168990029462704         0.296320805607773          0.62561856072969         0.435858588580919
           0.649115474956452         0.744692807074156         0.780227435151377         0.446783749429806
  Column 5
           0.306349472016557
           0.508508655381127
            0.51077156417211
           0.817627708322262
           0.794831416883453
           0.644318130193692

[Stephen23]

@trey: see my edited answer.

[trey]

@Stephen sorry I was on holiday ! your solution was perfect for my problem. thank you :)