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Run programm in background without using "start"

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MD on 8 Sep 2018
Commented: MD on 10 Sep 2018
Hello everyone!
My question is related to this one. I am trying to run my program in the background using the system command. However, if I understood correctly, when I add "start /b" to the command it does not wait for the other program to finish before continuing with the other operations.
Here is the input line for system that starts the program and waits for it to finish, however, opens in the foreground:
"energyPLAN.exe" -i "energyPlan Data\Data\Portugal_2050_tmp.txt" -ascii "Outputs\Portugal_2050_out"
"energyPLAN.exe" is the program, "energyPlan Data\Data\Portugal_2050_tmp.txt" is the input file and "Outputs\Portugal_2050_out" the output file.
This is the line that starts the program in the background, but does not wait for energyPLAN.exe to finish:
start /b "title" "energyPLAN.exe" -i "energyPlan Data\Data\Portugal_2050_tmp.txt" -ascii "Outputs\Portugal_2050_out"
What is the correct input that starts the program in the background but waits for it to finish?
Thanks in advance!
MD on 9 Sep 2018
I am sorry but I don't know too much about DOS. Where exactly would I need to put /wait in my string?

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Answers (1)

Walter Roberson
Walter Roberson on 9 Sep 2018
There is no way to do that using system().
You can use .NET to start processes that run in the background.
MD on 10 Sep 2018
I tried that as well. Unfortunately, it seems like I am out of luck because the program is still opened in the foreground. I also tried to set it to minimized but it also doesn't work.

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