Transfer from Decimal to Percentage?

Hi guys,

I have a Matrix A =

[1 2 3

4 5 6

7 8 9]

How I can get Matrix B =

[100% 200% 300%

400% 500% 600%

700% 800% 900%]?

Sprintf might work but I don't know how to use it. Thanks in advance.

[Walter Roberson]

You cannot get it as a numeric matrix, as numeric matrices cannot contain '%' characters.

[Xiao Tang]

Then how can I transfer it to string or cell array? As long as there follows '%'.

I was wondering if there is a function to do this...

Answer 1

[Walter Roberson]

thisfmt = [ repmat(' %.3f%%', 1, size(A,2)) '\n'];
B = sprintf( thisfmt, A.' );
B(1) = '[';
B(end) = ']';

This creates the output as a single string.

[Xiao Tang]

Thanks first. I was wondering if there is a way to create a 3 by 3 matrix instead of a scalar?

And the result is 100 times smaller.

[Walter Roberson]

100 * A.' to get the 100 times bigger.

Anyhow:

B = arrayfun(@(V) sprintf('%f%%', V), 100*A, 'Uniform', 0);

This will not, however, produce the result you had asked for: it will instead produce

B = { '100%' '200%' '300%'; '400%' '500%' '600%'; '700%' '800%' '900%'};

[Image Analyst]

Did he really want the square brackets (and question mark) in the output, or was he just using that because he was trying to indicate an array of some type?

[Xiao Tang]

The brackets are not necessary. I just want to find a quick way to transfer a particular matrix out of several matrix into percent format.

[Image Analyst]

So does the solution offered by Walter (a cell array of strings) work for you? Is so, mark this as "Accepted."

[Tom]

for what it's worth, if you want it in a cell array:

A=reshape(1:9,3,3)';

cellfun(@(x) sprintf('%0.1f%%',x*100),num2cell(A),'UniformOutput',false)

[Xiao Tang]

Thanks Tom! That's perfect!

[geopap]

Tom this works great!! Thanks