the polyarea function gives the wrong area

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Hi, I have a question with the polyarea function
x = [0 3 3 0 0 1 1 2 2 1]; y = [0 0 3 3 0 1 2 2 1 1];
With this curve the value it gives is 8, which is correct
However I made a very similar curve
x = [0 0.4258 0.4258 0 0.009 0.4168 0.4168 0.009 0.009]; y = [0 0 0.1807 0.1807 0 0.009 0.009 0.1717 0.1717 0.009];
and the value it gives is polyarea (x, y) -> 0.1433. And the value that should give is 0.010593
someone knows why ?

3 Comments

The later dimensions are not the same
YOu have not copied entire x. To use polyarea your order of the coordinates should follow a order..if not you will get wrong area. Give the entire x. In this case x is 1X9 and y is 1X10. So, we cannot apply polyarea.
Sorry, it's true
These are the vectors x, y
x = [0 0.4258 0.4258 0 0.009 0.4168 0.4168 0.009 0.009]; y = [0 0 0.1807 0.1807 0 0.009 0.009 0.1717 0.1717 0.009]; polyarea (x, y)
the result should be 0.010593
Thank you

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 Accepted Answer

I think MATLAB result is right, your expectation is wrong.
Check area
>> 0.1807*0.4258-(0.1807-2*0.009)*(0.4258-2*0.009)
ans =
0.010593000000000
>>
which is the same than MATLAB

5 Comments

x = [0 0.4258 0.4258 0 0 0.009 0.4168 0.4168 0.009 0.009]; y = [0 0 0.1807 0.1807 0 0.009 0.009 0.1717 0.1717 0.009]; polyarea(x,y)
ans=0.1433
x = [0 0.4258 0.4258 0 0 0.009 0.009 0.4168 0.4168 0.009];
y = [0 0 0.1807 0.1807 0 0.009 0.1717 0.1717 0.009 0.009];
polyarea(x,y)
ans =
0.010593000000000
PS: You enter the points in wrong order for the inner rectangle
Thank you very much Bruno
why this order is ok
and this order in wrong?
Yes the order of the second plot is wrong; MATLAB adds (instead of subtracts) the areas of the two rectangles if they run in the same direction (anti-clockwise for both here)

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More Answers (1)

What do you mean?
That the coordinate vectors are of different dimension? They are vectors of dimension 10 in both cases
Thank you

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