Using For Loop to find average of columns in a matrix

Hi I have a 4x365 matrix.

I'd like to know the average of the numbers in each column, so that's 365 values I'm looking for.

I can't use the mean() or sum() commands, and I'm trying to get this done using for loop.

X=ones(4,365)
cols=size(X,2);
for i=1:4
    for j=1:cols
        sum = sum + X(i,j);
    end
end

this gives me the final iteration. I need each iteration outputted into a new matrix so I may take the average.

Answer 1

[Stephen23]

Using a loop, without sum or mean:

X = randi(9,4,7)
N = size(X,1);
V = X(1,:);
for k = 2:N
    V = V + X(k,:);
end

And checking:

>> X
X =
   9   7   6   9   1   4   5
   5   1   5   6   2   5   8
   5   6   4   9   2   7   5
   1   6   8   4   8   5   3
>> V/N
ans =
   5.0000   5.0000   5.7500   7.0000   3.2500   5.2500   5.2500
>> mean(X,1)
ans =
   5.0000   5.0000   5.7500   7.0000   3.2500   5.2500   5.2500

[FanOf23]

I tried your code. Instead I made X = rand(4,365). However, the output V is just 4 values.

[Stephen23]

"Instead I made X = rand(4,365). However, the output V is just 4 values."

Try the edited answer, it works for me.

[FanOf23]

I got it thank you

Answer 2

[madhan ravi]

m=rand(4,365);

mean(m,1)

[madhan ravi]

you don't need to use loop to do the above

[Emmanuel Limaco]

Some assignments specifically instruct the student to use a for-loop and not the mean() command

Answer 3

[KSSV]

A = rand(4,365) ;
thesum = zeros(1,365) ;

for i = 1:4
    thesum = thesum+A(i,:) ;
end
iwant = thesum/4 ;