MATLAB Answers

0

How to solve error message in fsolve stating: "The vector of function values is near zero, as measured by the selected value of the function tolerance. However, the last step was ineffective"

Asked by Yonas Gezahegn on 14 Nov 2018
Latest activity Commented on by madhan ravi
on 22 Nov 2018
Dear all, I am trying to solve transcendental equations of TM mode using fsolve, but I constantly get error message stating:
"The vector of function values is near zero, as measured by the selected value of the function tolerance. However, the last step was ineffective."
Here are the code and myfun fiels, please help me!
Thxs!
% Given:
clear;clc;
mu_o = 4*pi*10^(-7);
mu_r = 1;
esp_o = (10^(-9))/(36*pi);
esp_r = 2.56;
esp_d = esp_o*esp_r;
mu_d = mu_o*mu_r;
h = 0.3175; % [cm]
f_c1 = 18.913e9; % from example 8-11 pp 17.
f = 0:f_c1/1000:2*f_c1;
b_z = 0; %Initialization
for f_index = 1:1:length(f)
w = (2*pi*f(f_index));
b_z = 793; % Initial point guessing
options = optimset('Display','iter','MaxFunEvals',1e20,'TolFun',1e-10,'TolX',1e-10);
b_z_sol = fsolve(@myfun, b_z, options);
end
b_yd_sol = (sqrt(w.^2*mu_d*esp_d - b_z_sol.^2))/100; % [rad/cm] equ. 8-160c
a_sol = (sqrt(b_z_sol.^2 - (w.^2*mu_o*esp_o)))/100; % [rad/cm] equ. 8-160d
b_o = w*sqrt(mu_o*esp_o);
b_d = w*sqrt(mu_d*esp_d);
% Figure-a
subplot(2,1,1);
plot(f(f_index)/f_c1,real(b_z_sol));
hold on;
plot(f(f_index)/f_c1, real(b_yd_sol), ':');
plot(f(f_index)/f_c1, real(a_sol), '--');
hold off;
axis([0 f(f_index)/f_c1 0 9]);
xlabel('Normalized frequency (f/f_C_1)');
title('Attenuation and Phase Constants of TM^{Z}_m');
subplot(2,1,2);
% Figure-b
plot(b_o, w);
hold on;
plot(b_d, w);
plot(real(b_z_sol), w);
axis([0 13e2 0 2e11]);
xlabel('\beta_o \beta_z \beta_d');
ylabel('\omega(\beta_o \beta_z \beta_d)');
title('Dispersion Curve');
hold off;
% myfum.m file code:
function F = myfun(b_z)
global w;
mu_o = 4*pi*10^(-7);
mu_r = 1;
esp_o = (10^(-9))/(36*pi);
esp_r = 2.56;
esp_d = esp_o*esp_r;
mu_d = mu_o*mu_r;
h = 0.3175; % [cm]
f_c1 = 18.913e9; % from example 8-11 pp 417
f = 0:18.913e6:2*f_c1;
for f_index = 1:1:length(f)
end
w = (2*pi*f(f_index));
% Iteration equations for the three unknowns
b_yd = (sqrt(w.^2*mu_d*esp_d - b_z.^2))/100; % [rad/cm] equ. 8-160c
a = (sqrt(b_z.^2 - (w.^2*mu_o*esp_o)))/100; % [rad/cm] equ. 8-160d
F = (a*(esp_d/esp_o)) - (b_yd*h*tan(b_yd*h)); % equ 8-160b
end

  1 Comment

Please don’t close the question that have an answer becuase it will be deleted after 10 days if a question is closed.

Sign in to comment.

1 Answer

Answer by Alan Weiss
on 15 Nov 2018
 Accepted Answer

Without running your code, I can tell you that the exit message you give is NOT an error message. Read its first part:
"The vector of function values is near zero, as measured by the selected value of the function tolerance."
This means that fsolve found a solution. So I think that you should't worry about the second part of the message, which is about algorithm internals.
Alan Weiss
MATLAB mathematical toolbox documentation

  2 Comments

Thanks a lot Alan!
My problem is to plot a graph using the output results.
Can anyone can give me a hint please.
I don't understand what you want to plot. I suggest that you start a new question with some details.
Alan Weiss
MATLAB mathematical toolbox documentation

Sign in to comment.