Creating combinations of 3 vectors

I have a 3x3 array

A = [50,20,30; 55,25,35; 60,30,40] 

and want to produce the 27 combinations below. How can I do this?

Result = [50,20,30; 50,20,35; 50,20,40; 50,25,30; 50,25,35; 50,25,40; 50,30,30; 50,30,35; 50,30,40; 55,20,30; 55,20,35; 55,20,40; 55,25,30; 55,25,35; 55,25,40; 55,30,30; 55,30,35; 55,30,40; 60,20,30; 60,20,35; 60,20,40; 60,25,30; 60,25,35; 60,25,40; 60,30,30; 60,30,35; 60,30,40].

Thanks,

Matt

Answer 1

[Akira Agata]

One possible solution would be like this:

A = [50,20,30; 55,25,35; 60,30,40];
[p1,p2,p3] = ndgrid(1:3);
Result = [A(p3(:),1),A(p2(:),2),A(p1(:),3)];

[madhan ravi]

+1 neat

Answer 2

[Guillaume]

Akira's answer is how I'd do it. Just for the record here is another method

indices = dec2base(0:size(A, 1)^size(A, 2)-1, size(A, 1)) - '0' + 1 + (0:size(A, 2)-1)*size(A, 1);
A(indices)

Works for A up to 10 rows.

[Akira Agata]

What a coincidence!

Thank you for adding another solution :-)