ode45 Initial conditions are not at the same point
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Yijia Liu
on 24 Nov 2018
Answered: Pasindu Ranasinghe
on 22 Jul 2021
Hello everybody, I'm using ode45 to solve some easy differential equations.
Here are the equations that I have:
For now, I have the initial conditions:
As you can see, the initial conditions are in not the common case, which may look like:x(4)=a;y(4)=b;
The value of x and y gets from different point.
Any suggestion on the set of initial values for ode45?
Thank you in advance!
Meredith
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Accepted Answer
madhan ravi
on 24 Nov 2018
5 Comments
madhan ravi
on 28 Nov 2018
Anytime :) if you find the answer helpful and it answered your query make sure to accept the answer
More Answers (1)
Pasindu Ranasinghe
on 22 Jul 2021
Example Code
Use ode45() to find the approximate values of the solution at t in the range of 1 to 3
function ydot = eqns(t,y)
ydot=(t-exp(-t))/(y+exp(y));
end
###################################
%%Code
[t1,y1]=ode45(@eqns,[1.5 1], 0.5);
hold on;
[t2,y2]=ode45(@eqns,[1.5 3], 0.5);
hold off
t=[t1;t2];
y=[y1;y2];
plot(t,y,'-o')
HOPE YOU FIND THIS USEFULL
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