Initialization of array of structure

Hello

I have a created array of structure (named LD) which incrementes from 1 to no of database (eg LD(1) to LD(10)). The structure has some fields. After some time I need to re-initialise the structure.

I tried with following commands.

LD = [];

But, I lost the field names, how to initialise with out loosing the field names.

Answer 1

[Walter Roberson]

Experiment with

LD = LD(false);

[Thulasi Durai Durai Samy]

Hello Walter, many thanks for your help!!

It works perfect to re-initialise whole set of database. If I want to delete particular database in-between, how to modify the above code.

for example LD(1)-LD(10) array of structure exists, 

remove LD(4), it has  

LD(4).field1
LD(4).field2 
LD(4).field3
LD(4).field4

so that my final database size is LD(1) - LD(9)

[Thulasi Durai Durai Samy]

Hi Walter

I think LD(4) = [] should work, please correct me if I am wrong

[Walter Roberson]

Yes, that is fine.

[Walter Roberson]

For the clearing, you might be able to use

LD(:) = [];

Unfortunately I cannot test that at the moment.

Answer 2

[Nirmal]

You shouldnt do LD=[], instead you should change the field of each of the structure in the array.

Answer 3

[Conrad]

The following code should do the trick:

function is = StructInit(s)
        is = s;
        if isstruct(s)
            f = fields(s);
            for i = 1 : length(f);
                if isstruct(is.(f{i}))
                    is.(f{i}) = StructInit(is.(f{i}));
                else
                    is.(f{i}) = [];
                end
            end
        else
            is = [];
        end
    end

Here is an example how to use it:

% Create dummy structure.
a.a = 1;
a.b = '';
a.c = {};
a.d.a.a = 2;
a.d.a.b = 1;
a.d.b = {};

initialisedStruct = StructInit(a);

All the fields are initialised to []. If a field is a structure, that structure's fields will be initialised etc.

Conrad