Replacing NaNs with zero in a matrix within a cell array.

How to replace NaNs with 0 in a cell array that has the following anatomy 13x1 cell, Each cell is of size 63x63[double]. the cell name is 'a'.

Any help would be appreciated, Thank you in advance.

[Kevin Phung]

what do you mean by the 'cell name'

[Raza]

the name of the cell array is 'a'. sorry for the confusion.

Answer 1

[Walter Roberson]

a = cellfun(@(M) subsasgn(M, substruct('()', {isnan(M)}), 0), a, 'uniform', 0);

No loop needed... just ugly code.

[Raza]

the code works just fine for me, thank you for your help.

Answer 2

[Andy Campbell]

The fillmissing function is built for this, you just need to use cellfun since each of these doubles are included in the cell array.

nanless = cellfun(@(c) fillmissing(c,'constant',0), a,'UniformOutput',false)

If you don't want to use cellfun, since it looks like you data is all uniform you can also do this by putting each cell into an array, applyin fillmissing, and then reshaping it back into the cell array:

array = [a{:}]; % This works because they are all 63x63
array = fillmissing(array,'constant',0);
a = mat2cell(array, 63, ones(1,13)*63)

and of course this can all be one-lined

a = mat2cell(fillmissing([a{:}],'constant',0), 63, ones(1,13)*63);

Answer 3

[Omer Yasin Birey]

% a = cell(13,1);
% %initializing the values
% for i = 1:length(a)
% a{i} = nan(63,63);
% end

%removing the nans
for k = 1:size(a,1)
  for j = 1:size(a,2)
    a{k,j}(isnan(a{k,j}))=0; 
  
  end
end

[Raza]

thank you so much for your help.