Assignment has more non-singleton rhs dimensions than non-singleton subscripts

n=50;classes=9;deepth=103;for i=1 to 9; index=1;
btraindata{i,1}=zeros(n*n*(classes-1),1,2,deepth);
tbtraindata{i,1}(index,1,1,deepth)=trainclass{i}(k,:);
it is showing assignment has more non-singleton rhs dimensions than nons-singleton subscrits.
pls give me some solution.

1 Comment

What is the value of index?
What is the meaning of "i=1 to 9;"?

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Answers (1)

You can check this by your own. Insert these lines:
size(tbtraindata{i,1}(index,1,1,deepth))
size(trainclass{i}(k,:))
% before this line:
tbtraindata{i,1}(index,1,1,deepth)=trainclass{i}(k,:)
You will see, that the dimensions do not match. At least one of them is not, what it should be. The readers cannot guess, which one is correct.

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