how to replace 'NaN' values with any other values in a cell array

in this cell, how can i replace nan value?

for i=1:8 
    if ~isempty(d11{i})
        for ix= 1:length(d11{i})
            for j=1:length(d11{i}{ix})
                for w=1:length(d11{i}{ix}{j})
                for k=1:length(d11{i}{ix}{j}{w})
                     
    %                   if isnan(d11{i}{ix}{j}{w}(k))
    %                       d11{i}{ix}{j}{1}(k)=.000001;
    %                  end 
                    d11{i}{ix}{j}{w}(k)(cellfun(@isnan,d11{3}{1}{1}{2}(k)))={'0'}


                end
                end
            end
        end
    end
end

output: Error: ()-indexing must appear last in an index expression.

[Rik]

You are using parentheses twice. How deep is your cell array? 4 or 5 levels deep? And why isn't your commented code working?

Also, are you sure you want to assign a char array to your cell instead of a normal 0 (of type double)?

[SOUVIK DATTA]

hello sir,

thank you for your attention. I want to replace by anything, either by a character (to write or symbolise something) or by any numerical value (for calculation). so, I tried both, none worked.

And, the array is 4 level deep. My program is skipping the commented code, means it neither shows any error nor change the 'NaN' values.

right now, I am continuing my work by changing the'NaN' value individually when it comes, before it gets stored in cell. But I want to cange it all at once. Any help would be appreciated. thank you.

Answer 1

[Walter Roberson]

d11 = fixnan(d11);

function x = fixnan(x)
%will work no matter how many levels, including if cells are not consistent types
    if isnumeric(x)
        x(isnan(x)) = 0;
    elseif iscell(x)
        x = cellfun(@fixnan, x, 'uniform', 0);
    %else other types do nothing, return unchanged
    end
end

[Rik]

Elegant solution, +1.