ode23 and ode45 problem

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baran erbas
baran erbas on 26 May 2019
Commented: baran erbas on 27 May 2019
Suppose we have a differential equation dy/dx=-2x+4y^2 over the range x=0 to 1 with y(0)=0. I need to solve this question with 'ode23' and ode45 in matlab. Does anybody help me?
  2 Comments
John D'Errico
John D'Errico on 26 May 2019
Next time, why not make an effort to do your homework yourself? Then show what you tried and ask for someone to help fix it, if you do not succeed.
baran erbas
baran erbas on 26 May 2019
Because i have no idea about this question if you can give me an example solution i will try to solve my question.

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Accepted Answer

Stephan
Stephan on 26 May 2019
% Solve symbolic (blue line in plot)
syms y(x) x
eqn = diff(y,x) == -2*x+4*y^2
sol_symbolic = dsolve(eqn,y(0)==0);
fplot(sol_symbolic,[0 1])
hold on
% solve numeric with ode45 (red dots in plot)
[V, S] = odeToVectorField(eqn);
fun = matlabFunction(V,'vars', {'x','Y'});
[x, sol_numeric] = ode45(fun,[0 1], 0);
plot(x, sol_numeric,'or')
hold off
With this example code it should be possible to use ode23 also
  4 Comments
Jan
Jan on 27 May 2019
Almost nice.
function main
[y,x] = ode45(@H, [0,1], [0,1]);
% ^ ^ round parentheses
end
function xl = H(x,y)
xl = zeros(2,1);
xl(1) = x(2);
xl(2) = -2 * x + 4 * y^2;
end
Use @H instead of defining the function to be integrated as char 'H'. The latter is still working, but outdate for 15 years now.
baran erbas
baran erbas on 27 May 2019
I tried this but it gives error
Index exceeds the number of array elements (1).
Error in batu>H (line 7)
xl(1) = x(2);
Error in odearguments (line 90)
f0 = feval(ode,t0,y0,args{:}); % ODE15I sets args{1} to yp0.
Error in ode45 (line 115)
odearguments(FcnHandlesUsed, solver_name, ode, tspan, y0, options, varargin);
Error in batu (line 2)
[y,x] = ode45(@H, [0,1], [0,1]);
what is the problem???

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