i need to compare a matrix with a static table

  X= [11.9000   10.3000    9.5000
      10.3000    8.7000    9.5000
      9.5000     7.9000    9.5000
      11.1000    9.5000    9.5000]
  
  Y= [7.9     186.46
      8.7     205.17
      9.5     223.84
      10.3    242.49
      11.1    261.11
      11.9	279.69]
  
  Z=[7.9	196.39
     8.7	216.11
     9.5	235.79
     10.3	255.45
     11.1	275.07]
 
     
  A=[9.5	247.74
    10.3	268.4
    11.1	289.03
    11.9	309.62
    12.7	330.19]

i need to comare the first column from X with the first column from Y

second column from X with the first column from Z

third column from X with the first column from A

and choose the corrsponding number from the second column from Y, Z and A correspondingly

RESULT =[279.69   255.45  247.74
         242.49   216.11  247.74
         223.84   196.39  247.74
         261.11   235.79  247.74]

Answer 1

[dpb]

> [interp1(Y(:,1),Y(:,2),X(:,1)) interp1(Z(:,1),Z(:,2),X(:,2)) interp1(A(:,1),A(:,2),X(:,3))]
ans =
  279.6900  255.4500  247.7400
  242.4900  216.1100  247.7400
  223.8400  196.3900  247.7400
  261.1100  235.7900  247.7400
>> 

If you'll rearrange your naming scheme to use cell arrays or struct field names instead of multiple variables for A,Y,Z then you could write as a looping construct instead of duplicating same code with different variables.

Answer 2

[Bjorn Gustavsson]

OK, how do you need to compare the first column of X with the first column of Y? Correlation? length of difference-vector? Angle between vectors? If you describe what you need to do answers will come that much easier.

After a little bit of inspection ot seems you need to find the most identical component? If this is so, I suggest that you have a look at min, abs, using those two function would help you solve the task for one element of X and one column of Y Z and A? Once you worked that out use loops to repeat that step for all components in X.

HTH

[Omar Almahallawy]

so... can u give me an example on how to do that