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Write a function called eligible that helps the admission officer of the Graduate School decide whether the applicant is eligible for admission based on GRE scores. The function takes two positive scalars called v and q as in

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function admit=eligible(v,q);
if v>=92 && q>=88;
fprintf('true')
else
fprintf('false')
end
  6 Comments
Walter Roberson
Walter Roberson on 13 Nov 2023
eligible(99,88)
ans = logical
0
function admit = eligible(v,q);
avperc = mean([v,q]);
if avperc>= 92 && (v>88&&q>88)
admit = true;
else admit = false;
end
end
@Mikail this is a correct output for 99, 88, at least according to the question posted at https://www.mathworks.com/matlabcentral/answers/471264-write-a-function-called-eligible-that-helps-the-admission-officer-of-the-graduate-school-decide-whet#comment_723801 where is says that the individual scores must be over 88% . Over 88% means that 88% exactly is not eligible.

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Answers (9)

VIGNESH B S
VIGNESH B S on 13 Oct 2021
function res = eligible(v,q)
pass = logical(0);
avg = (v+q)/2;
if (avg>= 92 && v >88 && q>88)
pass = logical(1);
end
res = pass;
end

Steven Lord
Steven Lord on 11 Jul 2019
Nowhere in your function do you define the variable admit the function returns as its output. You haven't shown the full text of the homework question but I suspect it tells you to have your function return true or false instead of printing the text "true" or "false". To do that assign a value to the variable.
admit = true;
admit = false;
  7 Comments
Walter Roberson
Walter Roberson on 23 Sep 2019
q and v are numeric values. When you use the && operator between them, admit=q&&v is defined as
if q ~= 0
if v ~= 0
admit = true;
else
admit = false;
end
else
admit = false;
end
However, the assignment makes no mention of testing for zero or not.
In particular when you get to your else branch, admit=~q&&v then that would be true if q was 0 and v was non-zero, leading you to admit someone with a score of 0 for q when the assignment would require that they be rejected because 0>88 is false.

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Aramis
Aramis on 5 Feb 2024
This is the BEST FCKN ANSWER
function admit = eligible(v, q)
admit = mean([v q]) >= 92 && min([v q]) > 88;
end
  1 Comment
DGM
DGM on 5 Feb 2024
Edited: DGM on 5 Feb 2024
I was skeptical of the bold claim, but I'm pretty sure this is the cleanest out of all four threads. At least it breaks the pattern of bad practices that everyone keeps recycling.

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Jake Armitage
Jake Armitage on 14 Apr 2021
After enough struggle I am wondering who can help me understand why I'm returning errors from this program. Thanks
function admit = eligible(v,q)
avperc = mean([v,q]);
if avperc>= 92 && (v&&q>88)
admit = true;
else admit = false;
end
end
  5 Comments
Rik
Rik on 7 Jul 2021
One closes the if, the other closes the program.
While using an end to close the program is optional, it is recommended that you do. If functions are explicitly closed with an end, you can use nested functions and you can define local functions in a script.

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Tushar  Nagar
Tushar Nagar on 13 Dec 2021
Edited: DGM on 3 Mar 2023
function admit=eligible(v,q)
avg=(v+q)/2;
rv=false;rq=false;
if v>88 && avg>=92
rv=true;
end
if q>88 && avg>=92
rq=true;
end
admit=rv && rq;
end

Ankit Sharma
Ankit Sharma on 14 Jun 2022
Edited: DGM on 3 Mar 2023
creating a function to get the results
function admit = eligible(v,q) % taking input as question required
avg = (v+q)/2; % we have to find the average so we can compare it with required variables
if (v>88 && avg>=92) && (q>88 && avg>=92) % condition check (logically) wheather v is greater
% then 88 and average is greater than 92 and same we are going
% to check logically for q and submitting the result in admit
admit = true;
else % if above conndition not satisfied then running else function and return false if condition not satisfied
admit = false;
end
end

Alexandar
Alexandar on 28 Jun 2022
function admit = eligible(v,q)
avg = (v+q)/2;
if avg > 92
admit = true(1);
elseif v >= 88 && q >= 88
admit = false(0);
else admit = 0;
end
I have no clue why this keeps failing. Can somebody please explain why?
  2 Comments
Alexandar
Alexandar on 28 Jun 2022
function admit = eligible(v,q)
gre_avg = (v+q)/2;
if (gre_avg >= 92) && (v > 88 && q > 88)
admit = 1;
else
admit = 0;
end
Wait, please check why this code is incorrect. Thank you!
DGM
DGM on 3 Mar 2023
The output needs to be of class 'logical'. In this example, the outputs are 1 or 0 -- which are numeric.
The functions false() and true() are functions used to create constant-valued logical arrays, much like zeros() and ones() are used to create constant-valued numeric arrays. In the first example, true(1) creates a logical scalar, whereas false(0) creates an empty logical array.
You could cast the given numeric values to logical using logical()
admit = logical(1);
... or you could directly assign the appropriate logical scalar
admit = true;
... or you could realize that the output of a comparison is already a logical value.
function admit = eligible(v,q)
gre_avg = (v+q)/2;
admit = (gre_avg >= 92) && (v > 88 && q > 88);
end

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Idris jae
Idris jae on 25 Sep 2022
Edited: DGM on 3 Mar 2023
Thank you for bringing this here. All this while the solution was in the error message '' the variable admit must be a logical data type".
function admit = eligible (v,q)
avg= (v+q)/2;
if (avg>=92) && (v>88 && q>88)
admit=logical(1); %most previous contributions here are thesame except at this point
else
admit=logical(0); %... and here
end
end

Arah Cristal
Arah Cristal on 12 Oct 2022
function admit=eligible(v,q);
avg = (v+q)/2;
if (avg>=92 && v>88 && q>88);
admit = true
else
admit = false
end
  1 Comment
DGM
DGM on 12 Oct 2022
The output of the combined comparisons is a logical value, so there really isn't any need to conditionally assign the output. You already have it.
function admit = eligible(v,q)
avg = (v+q)/2;
admit = avg>=92 && v>88 && q>88;
end

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