What does a\\r\n1 mean in MATLAB?

I'm trying to solve this equation (eqn) in MATLAB for fp1. It spits out a solution. I have no idea to interpret it. How many root solutions are there? What does the a\r\\n1 mean? How do I interpret it?

syms f2 ep1 ep2 a1 a2 fp1 fp2 h e1 m1 mp R f r t1 f1

eqn = (((ep2*fp1 - ep1*fp2)*mp*(e1*m1*(ep2*f2*fp1*(fp2 - a2*mp) + ep1*fp2*(-(f1*fp2) + a2*f2*mp))*(h + R) + a2*f2*(-(ep2*f*f2*fp1*R) + ep1*f*f1*fp2*R - ep1*ep2*(f1 - f2)*mp*r*(h + R)))* (a1*ep1*ep2*f1*(f1 - f2)*mp*(ep2*f*f2*fp1*R - ep1*f*f1*fp2*R + ep1*ep2*(f1 - f2)*mp*r*(h + R)) + e1*(ep2^2*f*f2^2*fp1^2*R*t1 + ep1^2*f1*fp2*(f*f1*fp2*R*t1 - ep2*(f1 - f2)*mp*(h + R)*(-(fp1*m1) + a1*m1*mp + r*t1)) + ep1*ep2*fp1*(-2*f*f1*f2*fp2*R*t1 + ep2*(f1 - f2)*mp*(h + R)*(-(f2*fp1*m1) + a1*f1*m1*mp + f2*r*t1)))))/(e1*ep1*ep2*(ep2*f2*fp1 - ep1*f1*fp2)^2*(h + R)^2*(ep1*ep2*(f1 - f2)*(-(a2*f2*fp1) + a1*f1*fp2)*mp + e1*(ep2*f2*fp1*(fp2 - a2*mp) + ep1*fp2*(-(f1*fp2) + a2*f2*mp))*t1))) * (-1) ==0;

syssolv = solve(eqn,fp1)

ans =

(a2*f2*(R*ep1*f*f1*fp2 - ep1*ep2*mp*r*(R + h)*(f1 - f2)) - e1*ep1*fp2*m1*(R + h)*(f1*fp2 - a2*f2*mp))/(R*a2*ep2*f*f2^2 - e1*ep2*m1*(R + h)*(fp2 - a2*mp)*f2)

(ep1*fp2)/ep2

(ep1*f1*mp*(R^2*a1^2*e1^2*ep2^2*f1^2*m1^2*mp^2 + 2*R^2*a1^2*e1*ep2^2*f*f1^2*f2*m1*mp + R^2*a1^2*ep2^2*f^2*f1^2*f2^2 + 2*R^2*a1*e1^2*ep1*ep2*f1^2*fp2*m1^2*mp - 4*R^2*a1*e1^2*ep1*ep2*f1*f2*fp2*m1^2*mp + 2*R^2*a1*e1^2*ep2^2*f1*f2*m1*mp*r*t1 - 4*R^2*a1*e1^2*ep2*f*f1*f2*fp2*m1*t1 + 4*R^2*a1*e1*ep1*ep2^2*f1^2*f2*m1*mp*r - 4*R^2*a1*e1*ep1*ep2^2*f1*f2^2*m1*mp*r - 2*R^2*a1*e1*ep1*ep2*f*f1^2*f2*fp2*m1 - 2*R^2*a1*e1*ep2^2*f*f1*f2^2*r*t1 + R^2*e1^2*ep1^2*f1^2*fp2^2*m1^2 - 2*R^2*e1^2*ep1*ep2*f1*f2*fp2*m1*r*t1 + R^2*e1^2*ep2^2*f2^2*r^2*t1^2 + 2*R*a1^2*e1^2*ep2^2*f1^2*h*m1^2*mp^2 + 2*R*a1^2*e1*ep2^2*f*f1^2*f2*h*m1*mp + 4*R*a1*e1^2*ep1*ep2*f1^2*fp2*h*m1^2*mp - 8*R*a1*e1^2*ep1*ep2*f1*f2*fp2*h*m1^2*mp + 4*R*a1*e1^2*ep2^2*f1*f2*h*m1*mp*r*t1 - 4*R*a1*e1^2*ep2*f*f1*f2*fp2*h*m1*t1 + 8*R*a1*e1*ep1*ep2^2*f1^2*f2*h*m1*mp*r - 8*R*a1*e1*ep1*ep2^2*f1*f2^2*h*m1*mp*r - 2*R*a1*e1*ep1*ep2*f*f1^2*f2*fp2*h*m1 - 2*R*a1*e1*ep2^2*f*f1*f2^2*h*r*t1 + 2*R*e1^2*ep1^2*f1^2*fp2^2*h*m1^2 - 4*R*e1^2*ep1*ep2*f1*f2*fp2*h*m1*r*t1 +\\\r\n 2*R*e1^2*ep2^2*f2^2*h*r^2*t1^2 + a1^2*e1^2*ep2^2*f1^2*h^2*m1^2*mp^2 + 2*a1*e1^2*ep1*ep2*f1^2*fp2*h^2*m1^2*mp - 4*a1*e1^2*ep1*ep2*f1*f2*fp2*h^2*m1^2*mp + 2*a1*e1^2*ep2^2*f1*f2*h^2*m1*mp*r*t1 + 4*a1*e1*ep1*ep2^2*f1^2*f2*h^2*m1*mp*r - 4*a1*e1*ep1*ep2^2*f1*f2^2*h^2*m1*mp*r + e1^2*ep1^2*f1^2*fp2^2*h^2*m1^2 - 2*e1^2*ep1*ep2*f1*f2*fp2*h^2*m1*r*t1 + e1^2*ep2^2*f2^2*h^2*r^2*t1^2)^(1/2) - ep1*f2*mp*(R^2*a1^2*e1^2*ep2^2*f1^2*m1^2*mp^2 + 2*R^2*a1^2*e1*ep2^2*f*f1^2*f2*m1*mp + R^2*a1^2*ep2^2*f^2*f1^2*f2^2 + 2*R^2*a1*e1^2*ep1*ep2*f1^2*fp2*m1^2*mp - 4*R^2*a1*e1^2*ep1*ep2*f1*f2*fp2*m1^2*mp + 2*R^2*a1*e1^2*ep2^2*f1*f2*m1*mp*r*t1 - 4*R^2*a1*e1^2*ep2*f*f1*f2*fp2*m1*t1 + 4*R^2*a1*e1*ep1*ep2^2*f1^2*f2*m1*mp*r - 4*R^2*a1*e1*ep1*ep2^2*f1*f2^2*m1*mp*r - 2*R^2*a1*e1*ep1*ep2*f*f1^2*f2*fp2*m1 - 2*R^2*a1*e1*ep2^2*f*f1*f2^2*r*t1 + R^2*e1^2*ep1^2*f1^2*fp2^2*m1^2 - 2*R^2*e1^2*ep1*ep2*f1*f2*fp2*m1*r*t1 + R^2*e1^2*ep2^2*f2^2*r^2*t1^2 + 2*R*a1^2*e1^2*ep2^2*f1^2*h*m1^2*mp^2 + 2*R*a1^2*e1*ep2^2*f*f1^2*f2*h*m1*mp + 4*R*a\\\r\n1*e1^2*ep1*ep2*f1^2*fp2*h*m1^2*mp - 8*R*a1*e1^2*ep1*ep2*f1*f2*fp2*h*m1^2*mp + 4*R*a1*e1^2*ep2^2*f1*f2*h*m1*mp*r*t1 - 4*R*a1*e1^2*ep2*f*f1*f2*fp2*h*m1*t1 + 8*R*a1*e1*ep1*ep2^2*f1^2*f2*h*m1*mp*r - 8*R*a1*e1*ep1*ep2^2*f1*f2^2*h*m1*mp*r - 2*R*a1*e1*ep1*ep2*f*f1^2*f2*fp2*h*m1 - 2*R*a1*e1*ep2^2*f*f1*f2^2*h*r*t1 + 2*R*e1^2*ep1^2*f1^2*fp2^2*h*m1^2 - 4*R*e1^2*ep1*ep2*f1*f2*fp2*h*m1*r*t1 + 2*R*e1^2*ep2^2*f2^2*h*r^2*t1^2 + a1^2*e1^2*ep2^2*f1^2*h^2*m1^2*mp^2 + 2*a1*e1^2*ep1*ep2*f1^2*fp2*h^2*m1^2*mp - 4*a1*e1^2*ep1*ep2*f1*f2*fp2*h^2*m1^2*mp + 2*a1*e1^2*ep2^2*f1*f2*h^2*m1*mp*r*t1 + 4*a1*e1*ep1*ep2^2*f1^2*f2*h^2*m1*mp*r - 4*a1*e1*ep1*ep2^2*f1*f2^2*h^2*m1*mp*r + e1^2*ep1^2*f1^2*fp2^2*h^2*m1^2 - 2*e1^2*ep1*ep2*f1*f2*fp2*h^2*m1*r*t1 + e1^2*ep2^2*f2^2*h^2*r^2*t1^2)^(1/2) - R*e1*ep1^2*f1^2*fp2*m1*mp - e1*ep1^2*f1^2*fp2*h*m1*mp + e1*ep1*ep2*f2^2*h*mp*r*t1 - R*a1*e1*ep1*ep2*f1^2*m1*mp^2 - a1*e1*ep1*ep2*f1^2*h*m1*mp^2 + 2*R*e1*ep1*f*f1*f2*fp2*t1 + R*a1*ep1*ep2*f*f1*f2^2*mp - R*a1*ep1*ep2*f*f1^2*f2*mp + R*e1\\\r\n*ep1^2*f1*f2*fp2*m1*mp + R*e1*ep1*ep2*f2^2*mp*r*t1 + e1*ep1^2*f1*f2*fp2*h*m1*mp - R*e1*ep1*ep2*f1*f2*mp*r*t1 - e1*ep1*ep2*f1*f2*h*mp*r*t1 + R*a1*e1*ep1*ep2*f1*f2*m1*mp^2 + a1*e1*ep1*ep2*f1*f2*h*m1*mp^2)/(2*e1*ep2*f2*(R*f*f2*t1 - R*ep1*f1*m1*mp + R*ep1*f2*m1*mp - ep1*f1*h*m1*mp + ep1*f2*h*m1*mp))

(ep1*f2*mp*(R^2*a1^2*e1^2*ep2^2*f1^2*m1^2*mp^2 + 2*R^2*a1^2*e1*ep2^2*f*f1^2*f2*m1*mp + R^2*a1^2*ep2^2*f^2*f1^2*f2^2 + 2*R^2*a1*e1^2*ep1*ep2*f1^2*fp2*m1^2*mp - 4*R^2*a1*e1^2*ep1*ep2*f1*f2*fp2*m1^2*mp + 2*R^2*a1*e1^2*ep2^2*f1*f2*m1*mp*r*t1 - 4*R^2*a1*e1^2*ep2*f*f1*f2*fp2*m1*t1 + 4*R^2*a1*e1*ep1*ep2^2*f1^2*f2*m1*mp*r - 4*R^2*a1*e1*ep1*ep2^2*f1*f2^2*m1*mp*r - 2*R^2*a1*e1*ep1*ep2*f*f1^2*f2*fp2*m1 - 2*R^2*a1*e1*ep2^2*f*f1*f2^2*r*t1 + R^2*e1^2*ep1^2*f1^2*fp2^2*m1^2 - 2*R^2*e1^2*ep1*ep2*f1*f2*fp2*m1*r*t1 + R^2*e1^2*ep2^2*f2^2*r^2*t1^2 + 2*R*a1^2*e1^2*ep2^2*f1^2*h*m1^2*mp^2 + 2*R*a1^2*e1*ep2^2*f*f1^2*f2*h*m1*mp + 4*R*a1*e1^2*ep1*ep2*f1^2*fp2*h*m1^2*mp - 8*R*a1*e1^2*ep1*ep2*f1*f2*fp2*h*m1^2*mp + 4*R*a1*e1^2*ep2^2*f1*f2*h*m1*mp*r*t1 - 4*R*a1*e1^2*ep2*f*f1*f2*fp2*h*m1*t1 + 8*R*a1*e1*ep1*ep2^2*f1^2*f2*h*m1*mp*r - 8*R*a1*e1*ep1*ep2^2*f1*f2^2*h*m1*mp*r - 2*R*a1*e1*ep1*ep2*f*f1^2*f2*fp2*h*m1 - 2*R*a1*e1*ep2^2*f*f1*f2^2*h*r*t1 + 2*R*e1^2*ep1^2*f1^2*fp2^2*h*m1^2 - 4*R*e1^2*ep1*ep2*f1*f2*fp2*h*m1*r*t1 +\\\r\n 2*R*e1^2*ep2^2*f2^2*h*r^2*t1^2 + a1^2*e1^2*ep2^2*f1^2*h^2*m1^2*mp^2 + 2*a1*e1^2*ep1*ep2*f1^2*fp2*h^2*m1^2*mp - 4*a1*e1^2*ep1*ep2*f1*f2*fp2*h^2*m1^2*mp + 2*a1*e1^2*ep2^2*f1*f2*h^2*m1*mp*r*t1 + 4*a1*e1*ep1*ep2^2*f1^2*f2*h^2*m1*mp*r - 4*a1*e1*ep1*ep2^2*f1*f2^2*h^2*m1*mp*r + e1^2*ep1^2*f1^2*fp2^2*h^2*m1^2 - 2*e1^2*ep1*ep2*f1*f2*fp2*h^2*m1*r*t1 + e1^2*ep2^2*f2^2*h^2*r^2*t1^2)^(1/2) - ep1*f1*mp*(R^2*a1^2*e1^2*ep2^2*f1^2*m1^2*mp^2 + 2*R^2*a1^2*e1*ep2^2*f*f1^2*f2*m1*mp + R^2*a1^2*ep2^2*f^2*f1^2*f2^2 + 2*R^2*a1*e1^2*ep1*ep2*f1^2*fp2*m1^2*mp - 4*R^2*a1*e1^2*ep1*ep2*f1*f2*fp2*m1^2*mp + 2*R^2*a1*e1^2*ep2^2*f1*f2*m1*mp*r*t1 - 4*R^2*a1*e1^2*ep2*f*f1*f2*fp2*m1*t1 + 4*R^2*a1*e1*ep1*ep2^2*f1^2*f2*m1*mp*r - 4*R^2*a1*e1*ep1*ep2^2*f1*f2^2*m1*mp*r - 2*R^2*a1*e1*ep1*ep2*f*f1^2*f2*fp2*m1 - 2*R^2*a1*e1*ep2^2*f*f1*f2^2*r*t1 + R^2*e1^2*ep1^2*f1^2*fp2^2*m1^2 - 2*R^2*e1^2*ep1*ep2*f1*f2*fp2*m1*r*t1 + R^2*e1^2*ep2^2*f2^2*r^2*t1^2 + 2*R*a1^2*e1^2*ep2^2*f1^2*h*m1^2*mp^2 + 2*R*a1^2*e1*ep2^2*f*f1^2*f2*h*m1*mp + 4*R*a\\\r\n1*e1^2*ep1*ep2*f1^2*fp2*h*m1^2*mp - 8*R*a1*e1^2*ep1*ep2*f1*f2*fp2*h*m1^2*mp + 4*R*a1*e1^2*ep2^2*f1*f2*h*m1*mp*r*t1 - 4*R*a1*e1^2*ep2*f*f1*f2*fp2*h*m1*t1 + 8*R*a1*e1*ep1*ep2^2*f1^2*f2*h*m1*mp*r - 8*R*a1*e1*ep1*ep2^2*f1*f2^2*h*m1*mp*r - 2*R*a1*e1*ep1*ep2*f*f1^2*f2*fp2*h*m1 - 2*R*a1*e1*ep2^2*f*f1*f2^2*h*r*t1 + 2*R*e1^2*ep1^2*f1^2*fp2^2*h*m1^2 - 4*R*e1^2*ep1*ep2*f1*f2*fp2*h*m1*r*t1 + 2*R*e1^2*ep2^2*f2^2*h*r^2*t1^2 + a1^2*e1^2*ep2^2*f1^2*h^2*m1^2*mp^2 + 2*a1*e1^2*ep1*ep2*f1^2*fp2*h^2*m1^2*mp - 4*a1*e1^2*ep1*ep2*f1*f2*fp2*h^2*m1^2*mp + 2*a1*e1^2*ep2^2*f1*f2*h^2*m1*mp*r*t1 + 4*a1*e1*ep1*ep2^2*f1^2*f2*h^2*m1*mp*r - 4*a1*e1*ep1*ep2^2*f1*f2^2*h^2*m1*mp*r + e1^2*ep1^2*f1^2*fp2^2*h^2*m1^2 - 2*e1^2*ep1*ep2*f1*f2*fp2*h^2*m1*r*t1 + e1^2*ep2^2*f2^2*h^2*r^2*t1^2)^(1/2) - R*e1*ep1^2*f1^2*fp2*m1*mp - e1*ep1^2*f1^2*fp2*h*m1*mp + e1*ep1*ep2*f2^2*h*mp*r*t1 - R*a1*e1*ep1*ep2*f1^2*m1*mp^2 - a1*e1*ep1*ep2*f1^2*h*m1*mp^2 + 2*R*e1*ep1*f*f1*f2*fp2*t1 + R*a1*ep1*ep2*f*f1*f2^2*mp - R*a1*ep1*ep2*f*f1^2*f2*mp + R*e1\\\r\n*ep1^2*f1*f2*fp2*m1*mp + R*e1*ep1*ep2*f2^2*mp*r*t1 + e1*ep1^2*f1*f2*fp2*h*m1*mp - R*e1*ep1*ep2*f1*f2*mp*r*t1 - e1*ep1*ep2*f1*f2*h*mp*r*t1 + R*a1*e1*ep1*ep2*f1*f2*m1*mp^2 + a1*e1*ep1*ep2*f1*f2*h*m1*mp^2)/(2*e1*ep2*f2*(R*f*f2*t1 - R*ep1*f1*m1*mp + R*ep1*f2*m1*mp - ep1*f1*h*m1*mp + ep1*f2*h*m1*mp))

Answer 1

[Walter Roberson]

It was an artifact for that one release. It indicates carriage return and linefeed. It only occurs in the printed representations and is not actually present in the expression.

[AR]

Would you be ablte to tell me how the expression looks like without it? I'm afraid of playing with the terms. Is there an online MATLAB portal I could use (with upgraded version) to see the results?

[Guillaume]

\r\n is just the new line character. They wouldn't change anything to the expression. You can just delete them.

[Walter Roberson]

https://www.mathworks.com/matlabcentral/answers/337896-odd-r-n-output-from-symbolic-multiplication#answer_265002

I posted code there