To get it's location as well, accept both outputs of max:
[maxValue, linearIndexesOfMaxes] = max(A(:));
Note that there can be the max value at more than one location. To get the rows and columns (instead of linear indexes), you can use ind2subs() or find():
This should be upvoted and/or somehow appear closer to the chosen answer, as M = max(A,'all') seems not to work at all in R2018b+ (returning the entire matrix).
M = max(A(:)) seems to work in R2018b+ and presumably universally.
The [] as the second input is required when you want to specify a dimension, including 'all'. The function call max(A, 'all') only works if A and 'all' are compatibly sized.
No, you don't need to include multiple calls to max. See the accepted Answer for approaches that call max only once regardless of how many dimensions the input argument has.
There is any way for a matrix size NxM to get the k maximum element in the whole matrix not in rows or colomns but in only elements. for example matrix A = [1 3 2 5, 7 9 12 8, 12 8 9 0] for K= 3 the 3 maximum elements are 12 9 and 8 and I want to return there location in the matrix.
The three maximum values are 12, 12, and 9, not 12, 9, and 8. If you are interested in the three maximum unique values, then you need to explicitly take into account that some values occur more than once.
k = 3;
uA = unique(A, 'sorted');
nresults = min(length(uA), k);
results = cell(nresults, 1);
for K = 1 : k
this_max = uA(end-K+1);
results{K,1} = this_max;
results{K,2} = find(A==this_max).';
end
disp(results)
{[12]} {[ 3 8]}
{[ 9]} {[ 5 9]}
{[ 8]} {[6 11]}
The output is a cell array, in which the first column gives you the value that is the maximum, and the second column gives you all the linear indices into the array. The code could be modified to give row and column outputs instead without much change.
The code does not assume that the number of occurrences is the same for each of the values (if that were known to be true then a numeric array could be created instead of a cell array.)
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