finding the right matrix

ni(i,1:2) is supposed to be a 2x2 vector but i keep getting a 1x2, help please

x = [0 0; 200 0; 200 25; 25 25; 25 200; 0 200;0 0];
n = size(x,1); % size will be equal to 7
n = n-1;
% initialize properties 
Asum = 0 ; % a scalar 
psum = zeros(1,2); % 1 x 2 matrix 
R = zeros(2,2); % 2 x 2 matrix

% 3. loop over sides 
for i = 1:n % 5 points 
  
 h(i) = norm(x(i,:));
   % from 3a as well 
 ni(i,1:2) = x(i,:)';     %------------------------------------
 b(i) =norm(x(i+1,:)-(x(i,:)));
 mi(i,1:2) = (x(i+1,:)-x(i,:))';
 
if h>0 
    ni = ni/h(i);
end
 if b(i)>0
  mi(i,1:2) = mi(i,1:2)/b(i);
end 

[Walter Roberson]

In order for ni(i, 1:2) to be 2x2 then i would need to be a vector of length 2. But you are in a for i loop so i is a scalar.

[alexis cordova]

so how will i go about making that a matrix while storing it as well

[Walter Roberson]

Do you want ni(i,1:2) to end up being two copies of x(i,:)' with both columns the same? If not then which two rows should be used, and should you be using two rows for norm(x(i,:));

[alexis cordova]

so when the loop is ran once im trying to get this below for mi and ni and aslo store it

but instead im getting

[Walter Roberson]

mi(i,1:2) = (x(i+1,:)-x(i,:))';

The left hand side is one row and two columns. Perhaps you want

mi(1:2, i) = (x(i+1,:)-x(i,:)).';