How to add Hann 5 cycles to the sine wave plot?

I would like to know how to add cycle to the sine plots?

The below one is a sine plot continuous how to make it short for only 5 cycles?where x here is the time and 200 is the load (kHz)

plot(x,sin(2*pi*200e3*x))

[darova]

One full cycle of sine is 2pi

You should make your argument of sine: 0 .. 2pi*5

Change your x such that:

0 ... 2pi*200e3 → 0 ... 2pi*5

[Ramesh Bala]

Hi Daravo

But my x is time vector

load('x.mat')

sf=200e3;

sinewave=sin(2*pi*sf*x);

figure(1);

plot(x, sinewave);

The above code gives a continuous sine plot

Note : kindly put your answers in the answer section as this will help me to accept it and vote it

Thanks

Answer 1

[darova]

One full cycle of sine is 2pi

You should make your argument of sine: 0 .. 2pi*5

[Ramesh Bala]

load ( 'x.mat')

sf = 200e3;

for cycle = 0:2*pi*5;

sinewave = sin (cycle * sf * x);

figure (1);

plot (x, sinewave);

end

something as such with a loop?

[darova]

Your code doesn't work :(

Please use special button for code inserting

[darova]

This should work

x = 0:31;
cycle = 0:2*pi*5;
sinwave = sin(cycle);
plot(x,sinwave)

[Ramesh Bala]

I want to add the load 200 kHz too That's why that sf is there

[darova]

But the argument of sin() can't be 200

Can't you add it before sin?

200*sin()

[darova]

DId i help you?

[Ramesh Bala]

load ( 'x.mat')
  
 cycle = 0:2*pi*5;
 sinewave = 200e3*sin(cycle*x); 
 figure (1);
 plot (x, sinewave);
 
 % i think it may give dimension error if I add 200e3?

[darova]

If you want multiply two vectors you should use dot

cycle.*x

For shorter expression you can write this

2e5*sin()

[Ramesh Bala]

still some dimension issues

sinewave = 2E5*sin(cycle.*x);

[darova]

Can't you do your calculation without x?

[Ramesh Bala]

no my x is a vector which is 1*4096 double and this indicates the time.

[darova]

Can you accept my answer?

[darova]

I did my best :(

[Ramesh Bala]

Ah kien problem Thank you so much :)